A. Let us assume the width of the pool = x
Then
Length of the pool = 3x + 3
Depth of the pool = 2(3x + 3) - 7
= 6x + 6 - 7
= 6x - 1
B. Area of the land space = Width * length
= x * (3x + 3)
= 3x^2 + 3x
C. Volume of the pool = (6x - 1) * (3x^2 + 3x)
= 18x^3 + 18x^2 - 3x^2 - 3x
= 18x^3 + 15x^2 - 3x
D. The highest degree is actually 3 and the number of terms that we get is also 3.
The point halfway between the two cities would be the midpoint, which is found by averaging the x and y coordinates. In this case the point would be ((3+7)/2, (4+1)/2) = (5, 2.5). The distance between the stadium and the high school can be found using the distance formula and then multiplying by 10.9 miles. That would get us 10.9sqrt((7-3)^2+(4-1)^2) = 54.5 miles if I did that mental math right.
Answer:
36 is the final value for the equation you posted
Step-by-step explanation:
We are told that = 3 and = −2.
Let's plug these values into the equation.
= (5 ( − 2) + (2 − )^2)
= (5 (3 − 2(−2)) + (2 − 3)^2)
= (5 (3 + 4) + (−1)^2)
= (5 (7) + 1)
= 35 + 1
= 36
Answer:
The Proof is given below.
Step-by-step explanation:
Given:
LN⊥KM,
KL≅ML
To Prove:
ΔKLN≅ΔMLN
Proof:
In Δ KLN and Δ MLN
KL ≅ ML ....……….{Given i.e Hypotenuse }
LN ≅ LN …………..{Reflexive Property}
∠ LNK ≅ ∠ LNM ……….{ LN ⊥ KM i.e Measure of each angle is 90° given}
Δ KLN ≅ Δ MLN ….{By Hypotenuse Leg Theorem}
....Proved
<span>In algebra, you can use function __Notation______ to express the idea that salary depends on the number of hours of training.
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