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denis-greek [22]
3 years ago
14

What is the circumference of a circle that has a radius of 10 centimeters? C=________

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0
C = 2πr
C = 2π(10)
C = 20π
C = 62.8

In short, Your Answer would be 62.8

Hope this helps!
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Let X be a random variable that is equal to the number of times a 5 is rolled in three rolls of a fair 5-sided die with the inte
Svetradugi [14.3K]

Answer:

Step-by-step explanation:

Note: If you have any queries related the answer please do comment. I would be very happy to resolve all your queries.

Firstly we will make PMF

For X=0, P=(4/5)^3=64/125

For X=1, P=C(3,1)*(1/5)*(4/5)^2=3*16/125=48/125

For X=2, P=C(3,2)*(1/5)^2*(4/5)=3*4/125=12/125

For X=3, P=C(3,3)*(1/5)^3=1/125

So,

E[X^2]=1*48/125+2^2*(12/125)+3^2/125=0.84

E[X]=48/125+12/125*2+1/125*3=0.6

So,

E[X]^2=0.36

7 0
3 years ago
If 3x + 7y = 47, AND 2x - y = 3 <br><br> What is the value x?
elixir [45]
X=4
y=5
work shown below

4 0
3 years ago
What is the Inter quartile Range <br> 5, 36, 15, 31
Greeley [361]

Answer:

The interquartile range would be 23.5.

3 0
3 years ago
Winter temperatures tend to be cold in the city of Johnstown. The table of values represents the temperature of Johnstown during
trapecia [35]

Answer:

Part A Part B Part C explained

Step-by-step explanation:

PART A: Extrema: relative minimums (4,-2) and maybe (7,-3) (uncertain because it’s an endpoint), relative maximums (6,0) and maybe (1,6) (uncertain because it’s an endpoint)

Zeros: (6,0), somewhere between t = 3 and t = 4 since the graph changes from positive to negative, and somewhere possibly between t = 6 and t = 7 unless the graph hits (6,0) and stays negative.

End behavior: We can guess that as x approaches infinity, the functions approaches negative infinity, and as x approaches negative infinity, the function approaches infinity.

Intervals of increase and decrease: Increasing on (4, 6), decreasing on (1, 4) and (6, 7)

PART B: The relative minimums indicate that the two lowest temperatures occurred on day 4 at -2°F and day 7 at -3°F. The relative maximums indicate that the weekly highs were day 1 at 6°F and day 6 at 0°F.

The zeros of the function represent when the temperature in Johnstown was 0°F. This happened sometime between days 3 and 4 and on day 6.

In the context of the problem, it doesn’t make sense to go an infinite number of degrees below zero. And, the end behavior is ignored because of the restricted range.

The intervals of increase indicate when the temperature is rising, and the intervals of decrease indicate when the temperature is dropping. The intervals where the values are positive indicate when the temperature is above 0°F. The intervals where the values are negative indicate when the temperature is below 0°F.

PART C: The domain is restricted to the number of days the town recorded the temperature. So, the domain is [1, 7].

The range represents the range of temperatures of Johnstown over the course of one week. So, the range is [-3, 6].

6 0
3 years ago
Slope of line that passes through points (2,1) and (17,-17)
mojhsa [17]

Answer: y = -1,2x + 3.4

Step-by-step explanation:

y = ax + b

(2,1)      => 1    = 2a + b (1)

(17,-17) => -17 =17a + b (2)

Using caculator Mode => 5 =>1

We get : a=- 1.2 , b = 3.4

=> y = -1.2x + 3.4

7 0
3 years ago
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