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dusya [7]
3 years ago
12

Verify that (sinx -cosx)^2=1-2sin(x)cos(x)

Mathematics
2 answers:
Artist 52 [7]3 years ago
6 0

Answer:

See below.

Step-by-step explanation:

Left side =  (sinx -cosx)^2 = sin^2 x + cos^2x - 2sinx cosx

Now sin^2 x + cos^2 x = 1 so we have:

1 - 2 sinx cosx = right side.

Nataly_w [17]3 years ago
5 0
<h3><em>(</em><em>sinx</em><em> </em><em>-</em><em> </em><em>cosx</em><em>)</em><em>^</em><em>2</em><em> </em><em>=</em><em> </em><em>(</em><em>sinx</em><em>)</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>(</em><em>cosx</em><em>)</em><em>^</em><em>2</em><em> </em><em>-</em><em> </em><em>2</em><em>s</em><em>i</em><em>n</em><em>x</em><em>c</em><em>o</em><em>s</em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>-</em><em>2</em><em>s</em><em>i</em><em>n</em><em>x</em><em>c</em><em>o</em><em>s</em><em>x</em></h3>
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