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3 years ago

Verify that (sinx -cosx)^2=1-2sin(x)cos(x)

Mathematics

2 answers:

Artist 52 [7]3 years ago

6 0

Answer:

See below.

Step-by-step explanation:

Left side = (sinx -cosx)^2 = sin^2 x + cos^2x - 2sinx cosx

Now sin^2 x + cos^2 x = 1 so we have:

1 - 2 sinx cosx = right side.

Nataly_w [17]3 years ago

5 0

<h3>(sinx - cosx)^2 = (sinx)^2 + (cosx)^2 - 2sinxcosx = 1-2sinxcosx</h3>

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3 years ago

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2 years ago

Read 2 more answers

Find the constant of variation k for the direct variation x -1 0 2 5 f(x) 2 0 -4 -10

Fofino [41]

Answer:

k = -2

Step-by-step explanation:

x -1 0 2 5

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3 years ago