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4 years ago

Acceleration due to gravity is ( always / sometimes / never ) the same on the earth.

Physics

1 answer:

love history [14]4 years ago

4 0

Sometimes, because acceleration due to gravity on Earth depends on how close you are to the Earth's center.

You might be interested in

Alexxx [7]

Answer:

120°

Explanation:

Draw a free body diagram. There are three forces acting on the traffic light. Two tension forces acting along the cables, and weight.

The tension forces have an angle θ between them. That means each tension force forms an angle of θ/2 with respect to the vertical. So the y component of each tension force is:

Ty = T cos (θ/2)

Sum of the forces in the y direction:

∑F = ma

Ty + Ty − W = 0

2 Ty = W

Substituting:

2 T cos (θ/2) = W

If W = T, then:

2 W cos (θ/2) = W

2 cos (θ/2) = 1

cos (θ/2) = 1/2

θ/2 = 60°

θ = 120°

6 0

4 years ago

A blender with a total resistance of 6 ohms runs on a voltage of 190 volts. How much current does it use? NEED TO KNOW ASAP PLEA

faltersainse [42]

<h2>Hello!</h2>

The answer is 31.67 Amps.

To solve the problem, we need to use Ohm's Law equation, which states that:

$V=IR$

Where,

V, is the voltage (in volts)

I, is the current (in Amps)

R, is the resistance (in Ohms)

We are given the following information:

$Voltage=190v\\Resistance=6\Omega\\$

So, using Ohm's Law equation and substituting the given information, we have:

$V=IR\\\\190v=I*6\Omega\\\\I=\frac{190v}{6\Omega}=31.67Amps$

Hence, we have that the current used by the blender is 31.67Amps.

Have a nice day!

4 0

3 years ago

The weight of an object four earth radii from the center of the earth is:

Komok [63]

Answer:

D. 1/16 It's weight on the surface.

Explanation:

As we know that the gravity due to earth at its surface is given as

$g = \frac{GM}{R^2}$

now at the distance of 4 radius of earth the gravity is given as

$g' = \frac{GM}{(4R)^2}$

so we can say that

$g' = \frac{g}{16}$

so here gravity becomes 1/16 times of the gravity due to earth on its surface

now we know that weight on the surface of earth is given as

$W = mg$

also the weight now at the given height is given by

$W' = mg/16$

so here correct answer will be

D. 1/16 It's weight on the surface.

8 0

4 years ago

An iron ball and an aluminum ball of mass 100 g each are heated to the same temperature and then cooled to a temperature of 20°

Y_Kistochka [10]

Becaused it the thing was cod that why

4 0

3 years ago

A 0.51-kg metal sphere oscillates at the end of a vertical spring. As the spring stretches from 0.12 m to 0.23 m (relative to it

den301095 [7]

Answer:

487.23 N/m

Explanation:

Given:

mass of metal sphere 'm'= 0.51kg

the spring stretches from 0.12 m to 0.23 m. Therefore,

$s_1}$ = 0.12m and $s_{2}$ = 0.23m

the speed of the sphere decreases from 6.7 to 3.3 m/s. Therefore,

$v_{1}$ = 6.7m/s and $v_2}$ =3.3m/s

In order to find spring constant, we apply law of conservation of energy. i.e

The change of the kinetic energy of sphere is equal to the change of potential energy of the spring.

So, Δ $E_{k} =$ Δ $E_{v}$

where,

Δ $E_{k} =$ 1/2 m ( $v_{1}$ - $v_2}$ )²

Δ $E_{v}$ = 1/2 k ( $s_1}$ - $s_{2}$ )²

1/2 m ( $v_{1}$ - $v_2}$ )² = 1/2 k ( $s_{2}$ - $s_1}$ )²

k= m [ ( $v_{1}$ - $v_2}$ )²/( $s_{2}$ - $s_1}$ )²

k= 0.51 [(6.7-3.3)²/ (0.23-0.12)²]

k= 487.23 N/m

Thus, the spring constant of the spring is 487.23 N/m

5 0

4 years ago