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4 years ago

Acceleration due to gravity is ( always / sometimes / never ) the same on the earth.

Physics

1 answer:

love history [14]4 years ago

4 0

Sometimes, because acceleration due to gravity on Earth depends on how close you are to the Earth's center.

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An average human weighs about 650 N. If each of two average humans could carry 1.0 C of excess charge, one positive and one nega

bezimeni [28]

Answer:

Distance, r = 3721.04 meters

Explanation:

It is given that,

Charges on both humans, $q_1=q_2=1\ C$

Electric force of attraction between them, F = 650 N

We need to find the separation between two humans. It can be solved using the following formula as :

$F=\dfrac{kq^2}{r^2}$

$r=\sqrt{\dfrac{kq^2}{F}}$

$r=\sqrt{\dfrac{9\times 10^9\times (1)^2}{650}}$

r = 3721.04 meters

So, the distance between the humans is 3721.04 meters. Hence, this is the required solution.

5 0

3 years ago

Harry and Hagrid needed to get money out of Gringotts bank. The bank cart was accelerating at a rate of 4 m/s2 and it had a mass

zhuklara [117]

F=m•a(squared)
F=8,000•4(squared)
F=8,000•16
F=128,000
then divide by 2 which is
64,000 Joules

4 0

3 years ago

Read 2 more answers

Is a whelk a carnivore?

arlik [135]

Herbivore: A animal/human that eats plant only.
Carnivore: A animal/human that eats meat.
Whelk is a name that implies to a variety of sea-snails / A large sea-snail. whelks are carnivores , they typically feed on worms ,mussels and other crustaceans.

7 0

3 years ago

Suppose that the loudspeaker in the problem had a mass of 500 kg and the ropes hung 20∘ from the vertical. Into which of the fol

nexus9112 [7]

The following intervals would you expect T(tension) to fall : <u>2000 to 4000 N </u>

<h3>Further explanation</h3>

The force acting on a system with static equilibrium is 0

$\large{\boxed{\bold{\sum F=0}}$

(forces acting as translational motion only, not including rotational forces)

$\displaystyle \sum F_x = 0\\\\ \sum F_y = 0$

We complete the questions:

A 20-kg loudspeaker is suspended 2.0 m below the ceiling by two ropes that are each 30? from vertical.

Find the value of T, the magnitude of the tension in either of the ropes.

Express your answer in newtons.

Suppose that the loudspeaker in the problem has a mass of 500 kg and the ropes hung 20? from the vertical. Into which of the following intervals would you expect T to fall? You don't have to calculate Texactly to answer this question; just make an estimate.

500 to 1000 N

1000 to 2000 N

2000 to 4000 N

4000 to 8000 N

8000 to 16,000 N

In a 500-kg loudspeaker system and two ropes that are each 20° from vertical, we see the forces acting on the y axis (vertical)

$\displaystyle \sum F_y = 0\\\\T1_y+T2_y-w=0\\\\T1~cos~20^o+T2~cos~20^o=m\times g$