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earnstyle [38]
3 years ago
15

An iron ball and an aluminum ball of mass 100 g each are heated to the same temperature and then cooled to a temperature of 20°

Physics
1 answer:
Y_Kistochka [10]3 years ago
4 0
Becaused it the thing was cod that why
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If an airplane is flying directly north at 300.0 km/h, and a crosswind is hitting the airplane at 50.0 km/h from the east, what
Rashid [163]

Answer:

magnitude = 304.14 km/h

direction: 9.46^o West of North

Explanation:

The final plane's vector velocity will be the result of the vector addition of one pointing North of length 300 km/h, another one pointing West of length 50 km/h.

To find the magnitude of the final velocity vector (speed) we need to apply the Pythagorean theorem in a right angle triangle with sides: 300 and 50, and find its hypotenuse:

|v|=\sqrt{300^2+50^2}=\sqrt{92500}  = 304.14 km/h

The actual direction of the plane is calculated using trigonometry, in particular with the arctan function, since the tangent of the angle can be written as:

tan(\theta)=\frac{50}{300} = \frac{1}{6} \\\theta = arctan(\frac{1}{6} ) = 9.46^o

So the resultant velocity vector of the plane has magnitude = 304.14 km/h,

and it points 9.46^o West of the North direction.

3 0
3 years ago
Calculate the most probable speed of an ozone molecule in the stratosphere
Marysya12 [62]

Answer:

v_{mp}=305.83 m/s

Explanation:

The temperature in stratosphere is generally about 270 K

molecular weight of an ozone molecule = 48 gm/mole

now formula for most probable velocity

v_{mp}= \sqrt{\frac{2RT}{M} }

plugging the values we get

v_{mp}= \sqrt{\frac{2\8.314\times270}{48} }

v_{mp}=305.83 m/s

7 0
3 years ago
(a) A space vehicle is launched vertically upward from the Earth's surface with an initial speed of vi that is comparable to but
ad-work [718]

Energy Conservation Theory,

(k+v)_i=(k+v)_f \quad \text { (No air resistone)}\\

\frac{1}{2} m v_i^2-\frac{G m M_\epsilon}{R_\epsilon}=0-\frac{G m M_\epsilon}{R_\epsilon+h}

\frac{1}{2} m v_i^2-\frac{G m M_\epsilon}{R_\epsilon}=0-\frac{G m M_\epsilon}{R_\epsilon+h}

v_{e x^2}{ }^2-v_i^2=\frac{v_{e^2 R_t} R_t}{R_t t h}\\&\frac{1}{v_{B C^2-v_1^2}^2}=\frac{R_E+h}{v_{e^2 R_E} R_E}\\\\\\h=\frac{R_E V_1^2}{v_{\text {esc }}^2-v_1^{\beta^2}}

<h3>What is law of  energy conservation?</h3>

The principle of energy conservation states that energy is neither created nor destroyed.  It may change from one sort to another. Just like the mass conservation rule, the legitimacy of the preservation of energy depends on experimental perceptions; hence, it is an experimental law. The law of preservation of energy, too known as the primary law of thermodynamics

To learn more about Energy Conservation Theory, visit;

brainly.com/question/8004680

#SPJ4

7 0
1 year ago
Which type of graph is best suited to show the breakdown of how this teacher weights each category ?
MArishka [77]

Answer:

pie graph?

Explanation:

6 0
3 years ago
Read 2 more answers
Why centre of mass equal to centre of gravity
Maksim231197 [3]
Because mass and distance determine gravity, so the more mass you have, the more gravity.
4 0
3 years ago
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