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pashok25 [27]
3 years ago
7

If the frog lands with a velocity equal to its average velocity and comes to a full stop 0.25s later, what is the frog’s average

acceleration?
Physics
1 answer:
Nina [5.8K]3 years ago
4 0

Answer:

Average accelation = -4V

Explanation:

a=\frac{V-V0}{t}

V=0 m/s (because the frog stopped)

V0 = V (average velocity)

t= 0,25 s

So;

a=\frac{V-V0}{t}=\frac{0-V}{0.25}=-4V

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