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Oksi-84 [34.3K]

2 years ago

7

Sublimation is used to describe

2 answers:

pshichka [43]2 years ago

6 0

Sublimation is the transition of a substance directly from the solid to the gas state, without passing through the liquid state; therefore:

c. the process of ice (solid) changing into water vapor (gas)

hope this helps:)

NNADVOKAT [17]2 years ago

5 0

The answer is c as this phase change refers to any change of a solid to gas.

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What is the input of energy for a device that provides 50 units of useful energy and has an efficiency of 0.55?

marshall27 [118]

If that's the case, then

      50 units = 0.55 x the input energy

Divide each side by 0.55 :

   50 units/0.55 = the input energy =

   <em> 90 and 10/11 units</em>

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4 years ago

A baseball of mass 1.23 kg is thrown at a speed of 65.8 mi/h. What is its kinetic energy?

frosja888 [35]

Given:

The mass of the ball is

$m=1.23\text{ kg}$

The speed of the ball is

$\begin{gathered} v=65.8\text{ mi/h} \\ \end{gathered}$

Required: calculate the kinetic energy of the baseball

Explanation: to calculate the kinetic energy of a body we will use the formula as

$K.E=\frac{1}{2}mv^2$

first, we convert velocity from mi/h into m/s.

we know that

$1\text{ mi=1609.34 m}$

and

$1\text{ h=3600 sec}$

then the velocity is

$\begin{gathered} v=\frac{65.8\times1602.34\text{ m}}{3600\text{ s}} \\ v=29.29\text{ m/s} \end{gathered}$

now plugging all the values in the above formula, we get

$\begin{gathered} K.E=\frac{1}{2}mv^2 \\ K.E=\frac{1}{2}\times1.23\text{ kg}\times(29.29\text{ m/s})^2 \\ K.E=527.61\text{ J} \end{gathered}$

Thus, the kinetic energy of the baseball is

$527.61\text{ J}$

4 0

2 years ago

What are Earth's mineral resources and how long might<br> reserves last?

amm1812

Reserves might last 53.3 years.

Earth’s mineral resources:

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3 years ago

Football is kicked at 23.4 m/s at a 38.5 angle. How far away does it land?

natulia [17]

Answer: go0gle will know the answer

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3 years ago

Read 2 more answers

A triangle ∆P QR has vertices P(3, 2, −4), Q(1, 0, −4), R(2, 1, 1). Use the distance formula to decide which one of the followin

777dan777 [17]

Answer:

a. FALSE

b.TRUE

C. FALSE

Explanation:

The formula fot the distance between two points is given as

$d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} +(z_{2}-z_{1})^{2}}\\$

hence we determine the distances between all the points

a.P(3,2,-4), Q(1,0,-4), R(2,1,1)

$PQ=\sqrt{(1-3)^{2} +(0-2)^{2} +(-4-(-4))^{2}}\\PQ=\sqrt{4+4+0}\\ PQ=\sqrt{8}$

For point PR

we have

$PR=\sqrt{(2-3)^{2} +(1-2)^{2} +(1-(-4))^{2}}\\PR=\sqrt{1+1+9}\\ PR=\sqrt{11}\\$

$|PQ|\neq |PR|$

B. For point RP

$RP=\sqrt{(3-2)^{2} +(2-1)^{2} +(-4-1)^{2}}\\RP=\sqrt{1+1+25}\\ RP=\sqrt{27}$

for point RQ we have

$RQ=\sqrt{(1-2)^{2} +(0-1)^{2} +(-4-1)^{2}}\\RQ=\sqrt{1+1+25}\\ RQ=\sqrt{27}$

|RP|=|R Q|

C.

$QP=\sqrt{(3-1)^{2} +(2-0)^{2} +(-4+4)^{2}}\\QP=\sqrt{4+4+0}\\ QP=\sqrt{8}$

For point Q R

$QR=\sqrt{(2-1)^{2} +(1-0)^{2} +(1-(-4))^{2}}\\QR=\sqrt{1+1+9}\\ QR=\sqrt{11}\\$

$QP\neq QR$

6 0

3 years ago