<u>Given data:</u>
wave length (λ) = 22 cm = 0.22 m,
speed of wave length(v) = 4 m/s ,
determine the frequency (f) = ?
We know that ,
wave length and frequency of light are closely related. The higher the frequency, shorter is the wavelength and vice-versa.
Mathematically, <em> λ = v/f -------------------- (i)</em>
<em> </em> where, λ = wave length (m)
v = speed of wave length (m/s)
f = frequency (Hz)
From the equation<em> </em><em>(i) </em>,<em> </em>
<em> </em><em>frequency (f) = v/λ</em>
= 4 / 0.22
= 18.18 /second
frequency (f) of the wave is 18 /sec or (18 Hz)
<em>Note:</em> frequency is defined as "<em>number of occurrences per unit time",</em> measured in<em> Hz</em>.
I believe it's one of the early stages of coal.
Answer:
False, Sunspots appear dark (in visible light) due to their low temperature(cooler) than rest of the sun
Explanation:
Sunspots appear dark because they are much cooler( have low temperature than the rest of the surface contained by Sun. As they appear dark, but still they have very temperature that's why so hot. Sunspots have temperatures ranges 3,500 Celsius (3773 kelvin) and the surrounding surface of the sun has a temperature much higher of about 5,500 Celsius(5773 Kelvin). Even if we see a sunspot alone in space, it will glow so brightly.
Learn more about sunspots :
brainly.com/question/27774496
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Thermal energy quantifies the amount of heat present in the body and is calculated through the equation,
H = mcpdT
where H is the heat, m is the mass, cp is the specific heat, and dT is the temperature difference. If all things are constant, and the thermal energy is halved then, dT should also be reduced to half.
Answer:
a)
b)
c)
d)
Explanation:
Given:
- length of muscle fibers,
- maximum stress on each fiber,
- Volume of muscles,
<em>∴Area of the muscle:</em>
a)
Maximum force developed by this muscle:
b)
Force when the muscles are 10% activated:
c)
- contraction in length of muscle,
- time taken for the contraction,
<u>Now, the speed of the muscle:</u>
d)
<u>Maximum force delivered when the muscle fibers are oriented at 15° from the tendons:</u>