The distance covered is 1000 m
Explanation:
The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

where
s is the distance covered
v is the final velocity
t is the time
a is the acceleration
For the rocket in this problem, we have:
v = 445 m/s is the final velocity
is the acceleration
t = 4.50 s is the time
Substituting, we find the distance covered:

Learn more about accelerated motion:
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The number of protons that strike the tumor each second is
protons.
<u>Given the following data:</u>
- Energy of proton =
Joules.
- Current = 84 nA to A =
Ampere.
- Energy of total dose =
Joules.
<u>Scientific data:</u>
- Charge of proton =
C.
To determine the number of protons that strike the tumor each second:
<h3>How to determine the number of
protons.</h3>
Mathematically, the quantity of charge per unit time is given by this formula:

<u>Where:</u>
- N is the number of protons.
- t is the time measured in seconds.
- e is the charge of protons.
Substituting the parameters into the formula, we have;
protons.
Read more on charges here: brainly.com/question/14372859
C. The membrane is inside the cell wall. The cell wall surrounds the membrane.
<span>Place a test charge in the middle. It is 2cm away from each charge.
The electric field E= F/Q where F is the force at the point and Q is the charge causing the force in this point.
The test charge will have zero net force on it. The left 30uC charge will push it to the right and the right 30uC charge will push it to the left. The left and right force will equal each other and cancel each other out.
THIS IS A TRICK QUESTION.
THe electric field exactly midway between them = 0/Q = 0.
But if the point moves even slightly you need the following formula
F= (1/4Piε)(Q1Q2/D^2)
Assume your test charge is positive and make sure you remember two positive charges repel, two unlike charges attract. Draw the forces on the test charge out as vectors and find the magnetude of the force, then divide by the total charge to to find the electric field strength:)</span>