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Anon25 [30]
3 years ago
7

Technician A says a short to voltage may or may not blow a fuse and may or may not affect more than one circuit. Technician B sa

ys that a short to ground​ (grounded) will usually cause a decrease in circuit resistance and an increase in current flow causing the fuse to blow. Which technician is​ correct?
A. Technician A only
B. Technician B only
C. Both A and B
D. Neither A nor B
Physics
1 answer:
Tomtit [17]3 years ago
6 0

Answer:

C. Both A and B

Explanation:

Fuses are rated by the amperage they can carry before heat melts the element. The fuse is ideal for protection against short circuits. Short circuits produce enough amperage to vaporize a fuse element and break connection in one cycle of a 60-cycle system.

Specifically, the voltage rating determines the ability of the fuse to suppress the internal arcing that occurs after a fuse link melts and an arc is produced.

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How does the input distance of a third-class lever compare to the output distance​
Alexandra [31]

Answer:

A first-class lever: fulcrum is between input and output force; second-class lever: output force is between input force and fulcrum; third-class lever: input force is between fulcrum and output force

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2 years ago
What is the purpose of the report​
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Answer:

The purpose of report : Reports communicate information which has been compiled as a result of research and analysis of data and of issues .

5 0
2 years ago
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In which way are the cathode rays deflected in the x-plates of the Cathode Ray Oscilloscope​
MrRissso [65]

Answer:

The cathode ray is deflected vertically to the fluorescent screen

Explanation:

.

4 0
3 years ago
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an 11 kg tool box is floating stationary in an orbiting spacecraft when a 79 kg astronaut, initially at rest, gives the tool box
snow_tiger [21]

The astronaut final velocity is 0.06 m/s to the right

Explanation:

In absence of external forces, the total momentum of the box-astronaut system is conserved.

At the beginnig, the total momentum of the two is zero, since they are at rest:

p_i = 0

While the final momentum, after the astronaut throws the box, is:

p_f=mv+MV

where

m = 11 kg is the mass of the box

M = 79 kg is the mass of the astronaut

v = -0.45 m/s (to the left) is the velocity of the box (we take left as negative direction)

V is the final velocity of the astronaut

The total momentum is conserved, so

p_i = p_f\\0=mv+MV

And solving , we find V:

V=-\frac{mv}{M}=-\frac{(11)(-0.45)}{79}=0.06 m/s

And the positive sign indicates that the direction is to the right.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

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6 0
3 years ago
A student performs this experiment and measures the bar to have a mass of 150g and length of 36cm. What is the moment of inertia
Ugo [173]

Answer:

The moment of inertia of the bar is 45\times10^{-4}\ kg-m^2

Explanation:

Given that,

mass of bar = 150 g

Length l = 36 cm

We need to calculate the moment of inertia of the bar

Using formula of moment inertia

I=\dfrac{1}{12}Ml^2

Where,

M = mass of the bar

L = length of the bar

Put the value into the formula

I=\dfrac{1}{12}\times150\times10^-3\times36\times10^{-2}

I=45\times10^{-4}\ kg-m^2

Hence, The moment of inertia of the bar is 45\times10^{-4}\ kg-m^2

4 0
3 years ago
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