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Anon25 [30]
4 years ago
7

Technician A says a short to voltage may or may not blow a fuse and may or may not affect more than one circuit. Technician B sa

ys that a short to ground​ (grounded) will usually cause a decrease in circuit resistance and an increase in current flow causing the fuse to blow. Which technician is​ correct?
A. Technician A only
B. Technician B only
C. Both A and B
D. Neither A nor B
Physics
1 answer:
Tomtit [17]4 years ago
6 0

Answer:

C. Both A and B

Explanation:

Fuses are rated by the amperage they can carry before heat melts the element. The fuse is ideal for protection against short circuits. Short circuits produce enough amperage to vaporize a fuse element and break connection in one cycle of a 60-cycle system.

Specifically, the voltage rating determines the ability of the fuse to suppress the internal arcing that occurs after a fuse link melts and an arc is produced.

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If a stone is dropped from a height of 400 feet, its height after t seconds is given by s = 400 − 16t2. Find its instantaneous v
soldier1979 [14.2K]

Answer:

v = -32 t

Explanation:

given,

s = 400- 16 t²

we know,

Velocity of an object is defined as the change in displacement per unit change in time.

velocity an also be return as

v = \dfrac{ds}{dt}

v = \dfrac{d}{dt}(400-16t^2)

v= 0 -2\times 16 t

v = -32 t

Hence, instantaneous velocity function given by v = -32 t

To calculate instantaneous velocity, you need to insert value of time.

ex, instantaneous velocity at t = 4 s

       v = -32 x 4 = -128 m/s.

5 0
3 years ago
ich of the following is not accurate when describing solids? A. The amount of pressure exerted by a solid is solely dependent on
Dafna11 [192]
The amount of solid does not affect how you are describing the solid so a is the answer
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3 years ago
The amount of friction divided by the weight of an object forms a unit less number called the
Romashka [77]

Answer:

Coefficient of friction.

Explanation:

The amount of friction divided by the weight of an object is equal to the coefficient of friction. It is a dimensional less number. It can be given by :

F=\mu N

N is normal force.

\mu = coefficient of friction

\mu=\dfrac{F}{N}

3 0
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Force is the first and mass is the second
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What type of radioactive decay is shown in this equation?
svp [43]
There is no <span>radioactive decay</span>
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