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solong [7]
2 years ago
9

Jaleesa is buying a round backyard pool. The distance around the edge of the pool is 38 feet. Find the area that the pool will c

over.
Mathematics
2 answers:
grin007 [14]2 years ago
7 0
Show the up too 100)( 7 •¥ ~=^10,.
Triss [41]2 years ago
5 0
Jaleesa is buying a round backyard pool. The distance around the edge of the pool is 38 feet. Let π = 3.14.

Find the area that the pool will cover.

•We need to use Area = π * Radius2 but first we have to find out the Radius.

Step 1: We know Circumference = π * Diameter. Which can also be written as Circumference = π * 2 * Radius.

So 38 ft = 3.14 * 2 * Radius (So we multiply 3.14 and 2 which equals 6.28)
38 ft = 6.28 * Radius (Since 6.28 is multiplying by the Radius we need to divide by 6.28)
6.28 6.28

6.05 = Radius

Step 2: Now we can calculate the Area.
Area= 3.14 * 6.052

Area= 3.14* 36.6

Area= 114.9 ft2.
. So about 114.93
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Rewrite using exponential notation \root(6)((4\pi )^(3))
Nezavi [6.7K]

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5 0
1 year ago
In ΔVWX, w = 520 cm, ∠W=93° and ∠X=68°. Find the length of x, to the nearest centimeter.
Pani-rosa [81]

Answer:

482.7972612 cm. Just round from here.

Step-by-step explanation:

Ah, the sine law questions. Ok so you know \frac{sin(A)}{a} = \frac{sin(B)}{b} = \frac{sin(C)}{c}. If you don't, voila. Obviously, the variables are different but we can use the same formula. So, we have

\frac{sin(X)}{x}  = \frac{sin(W)}{w}

Plug in:

\frac{sin(68)}{x} = \frac{sin(93)}{520}

The answer when solving for x is the above

7 0
3 years ago
Qual a altura máxima atingida por um projétil cuja trajetória pode ser descrita pela função: h(x) = –4x² + 5, sabendo que h é a
masya89 [10]

Answer:

A altura máxima é 5

Step-by-step explanation:

Matematicamente, a altura máxima pode ser obtida

A altura máxima é simplesmente o vértice da parábola

Começamos diferenciando a função Isso será -8x

Agora, defina -8x como 0

Isso significa que x = 0

Agora, substitua x = 0 de volta na equação temos

f (0) = -4 (0) ^ 2 + 5

f (0) = 5

A altura máxima é 5

6 0
3 years ago
What values of b satisfy 3(2b + 3)2 = 36?
KiRa [710]

the correct question is

What values of b satisfy 3(2b+3)^2 = 36


we have

3(2b+3)^2 = 36

Divide both sides by 3

(2b+3)^2 = 12

take the square root of both sides

( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3


b1=\frac{\sqrt{12}}{2} -\frac{3}{2}

b1=\sqrt{3} -\frac{3}{2}


b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}

therefore


the answer is

the values of b are

b1=\sqrt{3} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}


6 0
2 years ago
Read 2 more answers
Match each system to the correct choice.
pogonyaev

Answer:

Option A - Neither. Lines intersect but are not perpendicular. One Solution.

Option B - Lines are equivalent. Infinitely many solutions

Option C - Lines are perpendicular. Only one solution

Option D - Lines are parallel. No solution

Step-by-step explanation:

The slope equation is known as;

y = mx + c

Where m is slope and c is intercept.

Now, two lines are parallel if their slopes are equal.

Looking at the options;

Option D with y = 12x + 6 and y = 12x - 7 have the same slope of 12.

Thus,the lines are parrallel, no solution.

Two lines are perpendicular if the product of their slopes is -1. Option C is the one that falls into this category because -2/5 × 5/2 = - 1. Thus, lines here are perpendicular and have one solution.

Two lines are said to intersect but not perpendicular if they have different slopes but their products are not -1.

Option A falls into this category because - 9 ≠ 3/2 and their product is not -1.

Two lines are said to be equivalent with infinitely many solutions when their slopes and y-intercept are equal.

Option B falls into this category.

8 0
2 years ago
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