<u>Annotation</u>General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.
One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5 (first equation)
The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)
Plug the d-v-t relationship to the second equationd₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262
Plug the v₁ as (v₂+5) from the first equation2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.Find the velocity of the first car, use the first equationv₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.
Answer


Answer:
Step-by-step explanation:
100 is 4 times 25
25*4=100
so if we just multiply 26/25 we can find the percent
4*26/25=104/100
104%
Answer:
the first option
Step-by-step explanation:
solution:
distance: d=1/4 lc (because is a quarter of a circle)
length of the circumference: lc=2 pi r
pi: constant=3.14
radius of the circle: r=80 feet
replacing pi and r in the formula of lc:
lc=2 pi r
lc=2 (3.14) (80 feet)
lc=502.4 feet
replacing lc in the formula of d:
d=1/4 lc
d=1/4 (502.4 feet)
d=502.4/4 feet
d=125.6 feet
Answer:
The box is considered a cube so,
4 x 4 = 16
56 divided by 16 = 3.5 is your height
1/2 x 1/2 x 1/2 = 1/8.
56 divided by 1/8 = 7 cubes
68 can go into 757 11 times, the remainder would be 9
757÷68= 11 r 9 or 11 9/68