An ordered pair which makes both inequalities true is (-1, -3).
<h3>What is an ordered pair?</h3>
An ordered pair is a pair of two points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate or x-axis (abscissa) and the y-coordinate or y-axis (ordinate) on the coordinate plane of any graph.
Next, we would test the ordered pair with the given system of inequalities in order to determine which is true.
For ordered pair (-3, 5), we have:
y < –x + 1
5 < -(-3) + 1
5 < 3 + 1
5 < 4 (False).
For ordered pair (-2, 2), we have:
y < –x + 1
2 < -(-2) + 1
2 < 2 + 1
2 < 3 (True).
y > x
2 > -2 (True)
For ordered pair (-1, -3), we have:
y < –x + 1
-3 < -(-1) + 1
-3 < 1 + 1
-3 < 2 (True).
y > x
-3 > -1 (False)
For ordered pair (0, -1), we have:
y < –x + 1
-(-1) < -(0) + 1
1 < 1
1 < 1 (False).
y > x
-1 > 0 (False)
Read more on inequality here: brainly.com/question/27166555
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Answer:
the fist one
Step-by-step explanation:
Answer:
Step-by-step explanation:
If APB is measured in radians, then the arc length AB = APB(r) where r is the radius of the circle.
Answer:
-15
Step-by-step explanation:
