A drag racer starts her car from rest and accelerates at 5.5 m/s2 for the entire distance of 523 m. How long did it take the car
1 answer:
Answer:
t = 13.7 s or t = 14 s with proper significant figures
Explanation:
The initial speed is 0 m/s since the car starts from rest, acceleration is 5.5 m/s2 and distance is 523 m.
Since we have initial speed, acceleration and distance we can use the following formula to find the time. We can now use algebra to work out our answer.
d = vt + at²
523 = (0)t + ()(5.5)t²
523 = 2.8t²
186.8 = t²
13.7 s = t
(t = 14 s with proper significant figures)
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Answer:
When they are connected in series
The 50 W bulb glow more than the 100 W bulb
Explanation:
From the question we are told that
The power rating of the first bulb is
The power rating of the second bulb is
Generally the power rating of the first bulb is mathematically represented as
Where is the normal household voltage which is constant for both bulbs
So
substituting values
Thus the resistance of the second bulb would be evaluated as
From the above calculation we see that
This power rating of the first bulb can also be represented mathematically as
This power rating of the first bulb can also be represented mathematically as
Now given that they are connected in series which implies that the same current flow through them so
This means that
So when they are connected in series
This means that the 50 W bulb glows more than the 100 \ W bulb