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nadya68 [22]
2 years ago
8

A drag racer starts her car from rest and accelerates at 5.5 m/s2 for the entire distance of 523 m. How long did it take the car

to travel this distance? Answer in units of s.
Physics
1 answer:
ANEK [815]2 years ago
3 0

Answer:

t = 13.7 s or t = 14 s with proper significant figures

Explanation:

The initial speed is 0 m/s since the car starts from rest, acceleration is 5.5 m/s2 and distance is 523 m.

Since we have initial speed, acceleration and distance we can use the following formula to find the time. We can now use algebra to work out our answer.

d = vt + \frac{1}{2}at²

523 = (0)t + (\frac{1}{2})(5.5)t²

523 = 2.8t²

186.8 = t²

13.7 s = t

(t = 14 s with proper significant figures)

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27.0 mL to the nearest milliliter
Mila [183]

Answer:

27.0 milliliters is the nearest mililiter so 27.0 is the answer

Explanation:

8 0
3 years ago
A fisherman moves from one end of a boat to another
Naily [24]

Answer:

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5 0
2 years ago
If the humidity in a room of volume 410 m3 at 25 ∘C is 70%, what mass of water can still evaporate from an open pan? Express you
Keith_Richards [23]

Answer:

m=1864.68\ g

Explanation:

Given:

volume of air in the room, V=410\ m^3

temperature of the room, T=25+273=298\ K

<u>Saturation water vapor pressure at any temperature T K is given as:</u>

<u />p_{sw}=\frac{e^{(77.3450 + 0.0057\times T - \frac{ 7235}{T}  )}}{T^{8.2}}<u />

putting T=298 K we have

p_{sw}=3130\ Pa

<u>The no. of moles of water molecules that this volume of air can hold is:</u>

Using Ideal gas law,

P.V=n.R.T

n=\frac{P_{sw}.V}{R.T}

n=\frac{3130\times 410}{8.314\times 298}

n=518\ moles is the maximum capacity of the given volume of air to hold the moisture.

Currently we have 80% of n, so the mass of 20% of n:

m=(20\%\ of\ n)\times M}

where;

M= molecular mass of water

m=0.2\times 518\times 18

m=1864.68\ g is the mass of water that can vaporize further.

3 0
3 years ago
Some element can be either solid or liquid. At the melting point, the liquid has 8 × 10-22 J more enthalpy per atom than the sol
OlgaM077 [116]

Answer:

481.76 J/mol

133.33 K

Explanation:

N_A = Avogadro's number = 6.022\times 10^{23}

Change in enthalpy is given by

\Delta H=8\times 10^{-22}\times 6.022\times 10^{23}\\\Rightarrow \Delta H=481.76\ J/mol

Entropy is given by

\Delta S=6\times 10^{-24}\times 6.022\times 10^{23}\\\Rightarrow \Delta S=3.6132\ J/mol K

Latent heat of fusion is given by

L_f=\Delta H\\\Rightarrow L_f=481.76\ J/mol

The latent heat of fusion is 481.76 J/mol

Melting point is given by

T_m=\dfrac{L_f}{\Delta S}\\\Rightarrow T_m=\dfrac{8\times 10^{-22}\times 6.022\times 10^{23}}{6\times 10^{-24}\times 6.022\times 10^{23}}\\\Rightarrow T_f=133.33\ K

Melting occurs at 133.33 K

3 0
3 years ago
18. A person pulls horizontally with a force of 64 N on a 14-kg box. There is a force of friction between the box and the floor
MA_775_DIABLO [31]
  • since force=massxacceleration
  • therefore acceleration=force/mass
  • the resultant force=the acting force on the object-the frictional force
  • the resultant force=64-36=28N
  • therefore the acceleration=28/14=2m/sec^2
4 0
3 years ago
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