Answer:
Approximately
.
Assumption: the ball dropped with no initial velocity, and that the air resistance on this ball is negligible.
Explanation:
Assume the air resistance on the ball is negligible. Because of gravity, the ball should accelerate downwards at a constant
near the surface of the earth.
For an object that is accelerating constantly,
,
where
is the initial velocity of the object,
is the final velocity of the object.
is its acceleration, and
is its displacement.
In this case,
is the same as the change in the ball's height:
. By assumption, this ball was dropped with no initial velocity. As a result,
. Since the ball is accelerating due to gravity,
.
.
In this case,
would be the velocity of the ball just before it hits the ground. Solve for
.
.
Work is (force) times (distance). For Amy, you know both of them, and you can easily multiply them to find the amount of work. For Joe, the distance is zero, which should tell you all you need to know.
The period of the transverse wave from what we have here is 0.5
<h3>How to find the period of the transverse wave</h3>
The period of a wave can be defined as the time that it would take for the wave to complete one complete vibrational cycle.
The formula with which to get the period is
w = 4π
where w = 4 x 22/7
2π/T = 4π
6.2857/T = 12.57
From here we would have to cross multiply
6.2857 = 12.57T
divide through by 12.57
6.2857/12.57 = T
0.500 = T
Hence we can conclude that the value of T that can determine the period based on the question is 0.500.
Read more on transverse wave here
brainly.com/question/2516098
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All you would do is for a, 10 times 2 is 20 so it would be 20-dB
For b, 10 times 4 is 40 so it would be 40-dB
<span>For c, 10 times 8 is 80 so it would be 80-dB</span>
Answer:
5.62 m/s
Explanation:
Newton's law of motion can be used to determine the maximum speed of the elevator. In the question, we are given:
Force exerted by the elevator (R) = 1.7 times the weight of the passenger (m*g)
Thus: R = 1.7*m*g
Distance (s) = 2.3 m
Newton's second law of motion: R - m*g = m*a
1.7*m*g - m*g = m*a
a = 0.7*m*g/m = 0.7*g = 0.7*9.8 = 6.86 m/s²
To determine the maximum speed:



Therefore, the elevator maximum speed is equivalent to 5.62 m/s.