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Travka [436]
3 years ago
7

A spectroscope prism separates the white light from a star into a very wide spectrum. When widely spread, black lines appear in

the spectrum. Particular elements in a star create specific patterns in the lines.
What can you conclude about a spectroscope from this passage?

a
It allows scientists to determine a star's evolutionary stage.
b
It helps scientists measure a star's mass.
c
It helps scientists detect dark matter.
d
It allows scientists to determine which elements are present in a star.
Physics
2 answers:
topjm [15]3 years ago
5 0

Answer:

C. It helps scientists detect dark matter.

Explanation:

I got a 100% on my test. hope it help and I hope your having an awesome day :)

dolphi86 [110]3 years ago
5 0

Answer:

The answer is A)  

I hope this helps.

Explanation:

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This type of water occurs as a liquid resource that is dispersed through numerous holes, pores, fractures, and cavities in bodie
777dan777 [17]

Answer:

C

Explanation:

Although this may seem surprising, water beneath the ground is commonplace. Usually groundwater travels slowly and silently beneath the surface, but in some locations it bubbles to the surface at springs. The products of erosion and deposition by groundwater were described in the Erosion and Deposition chapter.

Groundwater is the largest reservoir of liquid fresh water on Earth and is found in aquifers, porous rock and sediment with water in between. Water is attracted to the soil particles and capillary action, which describes how water moves through a porous media, moves water from wet soil to dry areas.

Aquifers are found at different depths. Some are just below the surface and some are found much deeper below the land surface. A region may have more than one aquifer beneath it and even most deserts are above aquifers. The source region for an aquifer beneath a desert is likely to be far from where the aquifer is located; for example, it may be in a mountain area.

The amount of water that is available to enter groundwater in a region is influenced by the local climate, the slope of the land, the type of rock found at the surface, the vegetation cover, land use in the area, and water retention, which is the amount of water that remains in the ground. More water goes into the ground where there is a lot of rain, flat land, porous rock, exposed soil, and where water is not already filling the soil and rock.

The residence time of water in a groundwater aquifer can be from minutes to thousands of years. Groundwater is often called “fossil water” because it has remained in the ground for so long, often since the end of the ice ages.

8 0
3 years ago
Read 2 more answers
What is the centripetal acceleration of a ball on a string that is whirled horizontally over a boy’s head? The radius of the cir
Leya [2.2K]
Well the centripetal acceleration would be 9.82 squared. That is the correct answer. I hope this helped you. Have a great day! :)
4 0
3 years ago
Read 2 more answers
A woman does 236 J of work
GREYUIT [131]

Answer:

<h2>workdone = force × distance </h2><h2>236J = 18.9cos(o) × 24.4</h2><h2>236/24.4 = 18.9cos(o)</h2><h2>(0.5117)cos^-1 = (o)</h2><h2><u>59.21°</u></h2>

3 0
3 years ago
Read 2 more answers
A pilot wishes to flt his planne to an airport north of his current location
Ann [662]

Answer:

Time = 2758.62 seconds

Explanation:

Given the following data;

Speed = 290 m/s

Distance = 800 km to meters = 800 * 1000 = 800000

To find the time;

Time = distance/speed

Time = 800000/290

Time = 2758.62 seconds

Therefore, it will take the pilot 2758.62 seconds to reach the airport.

6 0
3 years ago
A 1.00-kg mass is attatched to a string 1.0m long and completes a horizontal circle in 0.25s. What is the centripetal accelerati
liraira [26]

-- The string is 1 m long.  That's the radius of the circle that the mass is
traveling in.  The circumference of the circle is  (π) x (2R) = 2π meters .

-- The speed of the mass is (2π meters) / (0.25 sec) = 8π m/s .

-- Centripetal acceleration is  V²/R = (8π m/s)² / (1 m) = 64π^2 m/s²

-- Force = (mass) x (acceleration) = (1kg) x (64π^2 m/s²) =

                                                         64π^2 kg-m/s² = 64π^2 N = about <span>631.7 N .

</span>
That's it.  It takes roughly a 142-pound pull on the string to keep
1 kilogram revolving at a 1-meter radius 4 times a second !<span> 
</span>
If you eased up on the string, the kilogram could keep revolving
in the same circle, but not as fast.

You also need to be very careful with this experiment, and use a string
that can hold up to a couple hundred pounds of tension without snapping. 
If you've got that thing spinning at 4 times per second and the string breaks,
you've suddenly got a wild kilogram flying away from the circle in a straight
line, at 8π meters per second ... about 56 miles per hour !  This could definitely
be hazardous to the health of anybody who's been watching you and wondering
what you're doing.


3 0
3 years ago
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