<u>Answer:</u> The moles of given hydrocarbon is 0.3 moles
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
We are given:
Given mass of ethane = 10.0 g
Molar mass of ethane = ![[(2\times 12)+(6\times 1)]=30g/mol](https://tex.z-dn.net/?f=%5B%282%5Ctimes%2012%29%2B%286%5Ctimes%201%29%5D%3D30g%2Fmol)
We need to divide the given value by the molar mass.
Putting values in above equation, we get:
In case of multiplication and division, the number of significant digits is taken from the value which has least precise significant digits. Here, the least precise number of significant digits are 1.
Hence, the moles of given hydrocarbon is 0.3 moles
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If you have a magnesium for every oxygen, then you have to start with two magnesiums. So the balanced equation is 2 Mg + O2 2 MgO.
And
CaCO3———→CaO + CO2
I hope it helped!
