Answer:
4.07L of a 0.110M NaF are needed
Explanation:
Based on the reaction:
SrCl₂(aq)+2NaF(aq)⟶SrF₂(s)+2NaCl(aq)
<em>1 mole of strontium chloride react with 2 moles of NaF</em>
<em />
361mL of 0.620M SrCl₂ solution has:
0.361L ₓ (0.620mol / L) = 0.22382 moles SrCl₂.
Moles of NaF for a complete reaction must be:
0.22382 moles SrCl₂ ₓ (2 mol NaF / 1 mol SrCl₂) = <em>0.44764 moles of NaF</em>
If you have a solution of 0.110M NaF, the moles of NaF needed are:
0.44764 moles of NaF ₓ (1L / 0.110mol NaF) = <em>4.07L of a 0.110M NaF are needed</em>
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<span>Answer:
I'm assuming the question is asking when it "jumps" from level 2 to level 1. In which case: 1/λ = Rh(1/nf^2 - 1/nfi^2) = 1.10x10^7 (1/1^2 - 1/2^2) = 1.10x10^7 ( 1 - 0.25) = 1.10 x10^7 (0.75) λ = 1.21 x 10^-7 m The wavelength produced will be about 1.21 x 10^ -7 m, or 121 nm.</span>
Explanation:
A chemical reaction where two chemical compounds exchange ions with each other is called a double displacement reaction.
Also, when an insoluble salt is formed due to chemical reaction between two chemical compounds is called a precipitation reaction.
For example, 
Here, ions are exchanged between the compounds 
and 
. Also, 
is the precipitate formed.
Hi :)
a. the reactants are zinc and copper oxide
b. the products are zinc oxide and copper
c. the elements are zinc, oxygen, and copper
d. the compounds are copper oxide and zinc oxide
hope this helps.
