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2 years ago

Plz I need help bad!

Mathematics

1 answer:

gtnhenbr [62]2 years ago

6 0

Answer:

72 bowls with 12 cups of cream

Step-by-step explanation:

First, I want to point out that the information, “3 pots of soup” is useless. So disregard that.

1/6 cups of cream for every bowl. That means, the assistant can prepare 6 bowls with one cup of cream.

1/6–bowl 1

1/6–bowl 2

1/6–bowl 3

1/6–bowl 4

1/6–bowl 5

1/6–bowl 6

At this point, 6 bowls are prepared. Add up all the cream that was used to make these 6 bowls.

1/6+1/6+1/6+1/6+1/6+1/6 = 6/6

Since 6/6=1, 1 whole cup of cream makes 6 bowls. That means 12 whole cups will make 12 x 6 = 72 bowls.

Hope this helps!

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Help please thank you!!!!!!!!!!!!

Tom [10]

Step-by-step explanation:

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5 0

2 years ago

3. Ramona drank 1 5/8 liters of water during soccer practice. She drank 1 1/4

VashaNatasha [74]

Answer:

The expression x = $\frac{13}{8}+\frac{5}{4}$ could be used to determine the amount of water drank altogether.

Step-by-step explanation:

Given that:

Amount of water drank during practice = $1\frac{5}{8} = \frac{13}{8}$ liters

Amount of water drank on the ride home = $1\frac{1}{4} = \frac{5}{4}$ liters

Let,

x be the total amount of water drank by Ramona.

x = Water drank during practice + Water drank on the ride home

x = $\frac{13}{8}+\frac{5}{4}$

Hence,

The expression x = $\frac{13}{8}+\frac{5}{4}$ could be used to determine the amount of water drank altogether.

5 0

2 years ago

5. Find the first, fourth, and tenth terms of the arithmetic

Lubov Fominskaja [6]

The first, fourth and tenth terms of the arithmetic sequence is $-6, -\frac{27}{5}$ and $-\frac{21}{5}$

Explanation:

The given rule for the arithmetic sequence is $A(n)=-6+(n-1)(\frac{1}{5} )$

We need to determine the first, fourth and tenth terms of the sequence.

To find the first, fourth and tenth terms, let us substitute $n=1,4,10$ in the general rule for the arithmetic sequence.

To find the first term, substitute $n=1$ in $A(n)=-6+(n-1)(\frac{1}{5} )$ , we get,

$A(1)=-6+(1-1)(\frac{1}{5} )$

$A(1)=-6+(0)(\frac{1}{5} )$

$A(1)=-6$

Thus, the first term of the arithmetic sequence is -6.

To find the fourth term, substitute $n=4$ in $A(n)=-6+(n-1)(\frac{1}{5} )$ , we get,

$A(2)=-6+(4-1)(\frac{1}{5} )$

$A(2)=-6+(3)(\frac{1}{5} )$

$A(2)=\frac{-30+3}{5}$

$A(2)=\frac{-27}{5}$

Thus, the fourth term of the arithmetic sequence is $-\frac{27}{5}$

To find the tenth term, substitute $n=10$ in $A(n)=-6+(n-1)(\frac{1}{5} )$ , we get,

$A(10)=-6+(10-1)(\frac{1}{5} )$

$A(10)=-6+(9)(\frac{1}{5} )$

$A(10)=-6+\frac{9}{5}$

$A(10)=-\frac{21}{5}$

Thus, the tenth term of the arithmetic sequence is $-\frac{21}{5}$

Hence, the first, fourth and tenth terms of the arithmetic sequence is $-6, -\frac{27}{5}$ and $-\frac{21}{5}$

3 0

2 years ago

Please help!!!!!!!!!!!!

MAXImum [283]

Answer:

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Step-by-step explanation:

6 0

2 years ago

Arrange the steps in the correct order to express cos3x in terms of cosx

ziro4ka [17]

The correct order to express cos3x in terms of cosx is; As shown in steps 1 to 9 below.

<h3>How to simplify Trigonometric Identities?</h3>

The steps to simplify the trigonometric identities cos 3x in terms of cos x are as follows;

Step 1; cos x = cos(2x + x)

Step 2; cos(2x) cosx - sin(2x) sinx

Step 3; 1 - 2sin^2x(cosx) -(2sinxcosx)sinx

Step 4; cosx - 2sin²x cosx - 2sin²x cosx

Step 5; cosx - 4sin²x cosx

Step 6; cosx( 1 - 4sin²x)

Step 7; cosx{1 - 4(1 - cos²x)}

Step 8; cosx{-3 + 4cos²x}

Step 9; 4cos³x - 3cosx

Read more about Trigonometric Identities at; brainly.com/question/7331447

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5 0

1 year ago