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xz_007 [3.2K]
4 years ago
12

Which fundamental identity is used in the second step of proof?

Mathematics
1 answer:
stepladder [879]4 years ago
4 0

Answer:

C) sin^2(Ф) + cos^2(Ф) = 1

Step-by-step explanation:

sin^2(Ф) - cos^2(Ф)sin^2(Ф) = sin^4(Ф)

LHS = sin^2(Ф) - cos^2(Ф)sin^2(Ф)

Step 1: sin^2(Ф) [ 1 - cos^2(Ф)]

Now we use the identity sin^2(Ф) + cos^2(Ф) = 1 because sin^2(Ф) = 1- cos^2(Ф)

Step 2: Using the above identity

sin^2(Ф) (sin^2(Ф)) = sin^4 (Ф)

Answer: C) sin^2(Ф) + cos^2(Ф) = 1

Hope this will helpful.

Thank you.

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aleksandrvk [35]

Answer:

Total magnification of microscope at this setting is 40X

Step-by-step explanation:

Total magnification of microscope is determined by multiplying the magnification power of individual lenses.

So if eyepiece has magnification power of 10X and objective lense has magnification power of 4X , the total magnification of microscope would be

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6 0
4 years ago
Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p
PIT_PIT [208]

Answer:

Colin has <em>8 sheets </em>left for his third class.

Step-by-step explanation:

Given that:

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Writing the equation:

\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

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So, the answer is:

Colin has <em>8</em> <em>sheets </em>left for his third class.

5 0
3 years ago
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Step-by-step explanation:

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