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S_A_V [24]
3 years ago
8

Ruby invested $6,200 in an account paying an interest rate of 4.3% compounded continuously. Assuming no deposits or withdrawals

are made, how much money, to the nearest hundred dollars, would be in the account after 12 years?
Mathematics
1 answer:
Andrew [12]3 years ago
6 0

Answer:

$9,399.20

Step-by-step explanation:

multiply the original amount by the percentage

6,200*4.3=26,660

Then divide 26,660 by 100

26,660/100= 266.6

Multiply 266.6 by 12

266.6*12=3199.2

<u>So, $3,199.20 were added to your account over 12 years </u>

Add $3,199.20 and $6,200

$3,199.20+$6,200=$9,399.20

So, after 12 years you would have $9,399.20 in your account

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Karen plans to drive to a national park that is 582.8 miles away her car gets 23.5 miles on 1 gallon of gasoline gasoline cost $
NARA [144]

Answer: The correct answer is $85.56

Step-by-step explanation:

If Karen gets 23.5 miles per one gallon of gas, we divide 582.8 miles by 23.5 to see how many gallons she will use to go the 582.8 miles. The answer is 24.8 gallons. (582.8/23.5=24.8)

We then multiply 24.8 ( the total amount of gallons) x $3.45 (per gallon)= $85.56 for the entire trip

3 0
4 years ago
A farming council takes a large random survey of US adults in which they ask how many times they ate a
Lady_Fox [76]

Answer:

Histogram A

Step-by-step explanation:

Because I was trying to find the answer but I got it wrong and it told me the answer <3

6 0
3 years ago
Alex scored 10 out of 50 in a test. what percentage does this represent?
melisa1 [442]
1/5 is your answer 
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3 0
3 years ago
Read 2 more answers
How do I factorise <br> 6-42x
Zepler [3.9K]

FACTORING: 6 - 42x

STEPS:
 
6 - 42x

-42x + 6

= -6(7x - 1)

FINAL ANSWER: -6(7x - 1)

4 0
3 years ago
Read 2 more answers
The computer that controls a bank's automatic teller machine crashes a mean of 0.60.6 times per day. What is the probability tha
OLEGan [10]

Answer:

0.6045 = 60.45% probability that, in any seven-day week, the computer will crash more than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The computer that controls a bank's automatic teller machine crashes a mean of 0.6 per day.

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash more than 3 times?

Either it crashes 3 or less times, or it crashes more than 3 times. The sum of the probabilities of these events is decimal 1. So

P(X \leq 3) + P(X > 3) = 1

We want P(X > 3). So

P(X > 3) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

P(X = 3) = \frac{e^{-4.2}*(4.2)^{3}}{(3)!} = 0.1852

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0150 + 0.0630 + 0.1323 + 0.1852 = 0.3955

P(X > 3) = 1 - P(X \leq 3) = 1 - 0.3955 = 0.6045

0.6045 = 60.45% probability that, in any seven-day week, the computer will crash more than 3 times.

3 0
4 years ago
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