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Genrish500 [490]
4 years ago
11

A copper wire has a circular cross section with a radius of 1.50 mm. (a) If the wire carries a current of 2.60 A, find the drift

speed of the electrons in the wire. (Assume the density of charge carriers (electrons) in a copper wire is n = 8.46 1028 electrons/m3.) m/s (b) All other things being equal, what happens to the drift speed in wires made of metal having a larger number of conduction electrons per atom than copper? Explain.
Physics
1 answer:
AleksAgata [21]4 years ago
5 0

Answer:

Part a)

v_d = 2.72 \times 10^{-5} m/s

Part b)

it is inversely depends on the number density so on increasing the number density the drift speed will decrease

Explanation:

Part a)

As we know that the cross-sectional radius is

r = 1.50 mm

now we will have

A = \pi r^2

A = \pi(1.50 \times 10^{-3})^2

A = 7.07 \times 10^{-6} m^2

now we know that

i = neA v_d

so we will plug in all data

2.60 = (8.46 \times 10^{28})(1.6 \times 10^{-19})(7.07\times 10^{-6})v_d

v_d = 2.72 \times 10^{-5} m/s

Part b)

As we know that

i = neAv_d

now if all other things are same

v_d = \frac{i}{neA}

since it is inversely depends on the number density so on increasing the number density the drift speed will decrease

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