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3 years ago

Answer this please, best answer gets brainliest!

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

8 0

Solve how much the salesperson makes in option A and use that value as the 5% of the total of sales to solve for option B

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Graph the function. f ( x ) = 1 3 x 2 − 2 x + 8 f(x)= 3 1 x 2 −2x+8

Reika [66]

Answer:

Ok ill get back to you when I figure it out so see you in 5 minutes!

7 0

3 years ago

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The tape diagram represents an equation, 1.75 Write an equation to represent the image.

rjkz [21]

Answer:

$5n=1.75$

Step-by-step explanation:

Given: tape diagram

To find: an equation to represent the image

Solution:

In the image, the area of the tape diagram indicating 1.75 is equal to the sum of areas of all the five parts in the diagram such that each part indicates n.

So, according to the given information, the equation is $5n=1.75$ .

Here, we have assumed that 1.75 represents an area of the first rectangle, and n represents the area of each of the small rectangle.

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3 years ago

Answer the question: 4x – 7 = 4x – 7

Pepsi [2]

X could equal anything because of these two equivalent problems on each side. This would be unsolvable, so JOT DOWN the words “no solution”.

3 0

3 years ago

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Exponential growth/decay problem 2

lapo4ka [179]

Answer:

a) decay

b) 2,950,000

c) 0.025

d) $f(x)=2950000(0.975)^x$

e) 2,409,123

Step-by-step explanation:

Part (a)

Exponential DECAY, since the population was decreasing annually.

Part (b)

Initial amount = 2,950,000 people (in the year 2000)

Part (c)

Decay factor = 2.5% = 0.025 (in decimal form)

Part (d)

General form of exponential decay function:

$f(x)=a(1-r)^x$

where:

a = initial amount
r = rate of decay (in decimal form)
x = time (in years)

Given:

a = 2950000
r = 0.025

$\implies f(x)=2950000(1-0.025)^x$

$\implies f(x)=2950000(0.975)^x$

Part (e)

To determine the city's population in 2008:

$x = 2008 - 2000 = 8$

$\begin{aligned}\implies f(8) & =2950000(0.975)^8\\ & = 2409123\: \sf(nearest\:whole\:number)\end{aligned}$

7 0

2 years ago

Find the area of the region that is inside r=3cos(theta) and outside r=2-cos(theta). Sketch the curves.

raketka [301]

Answer:

3√3

Step-by-step explanation:

r = 3 cos θ

r = 2 - cos θ

First, find the intersections.

3 cos θ = 2 - cos θ

4 cos θ = 2

cos θ = 1/2

θ = -π/3, π/3

We want the area inside the first curve and outside the second curve. So R = 3 cos θ and r = 2 - cos θ, such that R > r.

Now that we have the limits, we can integrate.

A = ∫ ½ (R² - r²) dθ

A = ∫ ½ ((3 cos θ)² - (2 - cos θ)²) dθ

A = ∫ ½ (9 cos² θ - (4 - 4 cos θ + cos² θ)) dθ

A = ∫ ½ (9 cos² θ - 4 + 4 cos θ - cos² θ) dθ

A = ∫ ½ (8 cos² θ + 4 cos θ - 4) dθ

A = ∫ (4 cos² θ + 2 cos θ - 2) dθ

Using power reduction formula:

A = ∫ (2 + 2 cos(2θ) + 2 cos θ - 2) dθ

A = ∫ (2 cos(2θ) + 2 cos θ) dθ

Integrating:

A = (sin (2θ) + 2 sin θ) |-π/3 to π/3

A = (sin (2π/3) + 2 sin(π/3)) - (sin (-2π/3) + 2 sin(-π/3))

A = (½√3 + √3) - (-½√3 - √3)

A = 1.5√3 - (-1.5√3)

A = 3√3

The area inside of r = 3 cos θ and outside of r = 2 - cos θ is 3√3.

The graph of the curves is:

desmos.com/calculator/541zniwefe

5 0

3 years ago