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3 years ago

What is 3 to the 5th power?

Mathematics

2 answers:

SashulF [63]3 years ago

8 0

729 is 3 to the 5th power

3 x 3 x 3 x 3 x 3 is 729

Luden [163]3 years ago

4 0

You multiply 3 times 3 is 9 that's 3 to the 2nd power so 9 times 3 is 27 that is to the third power and 27 times 3 is 81 that is to the 4th power and 81 times 3 is 243 that is to the fifth power
the correct answer is 243 <span />

You might be interested in

Write the conversion factor for converting meters to centimeters

posledela

Since we are converting meters to centimeters we are converting large to small.

Expect the answer to be a larger number. Here are some example of large to small:
2 weeks (larger unit) = 14 days (smaller unit) 14 is larger than 2
4 days (larger unit ) = 96 hours (smaller unit) 96 is larger than 4
Since there are 100cm in a meter, when we change meters to cm, we need a bigger number. The conversion factor is 100 and should be used as a multiplier.
Example: 47m x 100 = 4700 cm

7 0

3 years ago

If d(x)=9x^2 and g(x)=5x+7 then d(x)-g(x) can be rewritten as

Angelina_Jolie [31]

Answer:

$9x^2-5x-7$

Step-by-step explanation:

$d(x)=9x^2\\g(x)=5x+7\\d(x)-g(x)=\\(9x^2)-(5x+7)=\\9x^2-5x-7$

Hope this helps!

7 0

3 years ago

Read 2 more answers

Determine the volume of the figure. Use 3.14 for π. Round your answer to the nearest tenth. Show all of your work.

Ostrovityanka [42]

Answer:

1985 cubic units (written as un. with the cubed exponent)

Step-by-step explanation:

First, you find the volume of the cylinder

Here's the formula:

$V=\pi r^{2}h\\V=volume\\r=radius\\h=height$

Now, you plug in and solve.

$V=(3.14)(7.2^{2})(7.4)\\V=(3.14)(51.84)(7.4)\\V=(162.7776)(7.4)\\V=1204.55424\\rounded:\\V=1204.6$

Then, you find the volume of the dome.

Here's the formula:

$volume/of/a/sphere=\frac{4}{3}\pi r^{3}\\volume/of/a/dome:\\V=\frac{2}{3}\pi r^{3} \\V=volume\\r=radius$

Now, you just plug in and solve.

$V=(\frac{2}{3})(\pi)(r^{3})\\V=(\frac{2}{3})(3.14)(7.2^{3})\\V=(\frac{2}{3})(3.14)(373.248)\\V=(2.093)(373.248)\\V=781.208064\\rounded:\\V=781.2$

Finally, you add them together, and there's your answer!

$1204.6+781.2=1985.8$

Hope this helped!

<em>brainliest?</em>

8 0

3 years ago

You have a large jar that initially contains 30 red marbles and 20 blue marbles. We also have a large supply of extra marbles of

Dima020 [189]

Answer:

There is a 57.68% probability that this last marble is red.

There is a 20.78% probability that we actually drew the same marble all four times.

Step-by-step explanation:

Initially, there are 50 marbles, of which:

30 are red

20 are blue

Any time a red marble is drawn:

The marble is placed back, and another three red marbles are added

Any time a blue marble is drawn

The marble is placed back, and another five blue marbles are added.

The first three marbles can have the following combinations:

R - R - R

R - R - B

R - B - R

R - B - B

B - R - R

B - R - B

B - B - R

B - B - B

Now, for each case, we have to find the probability that the last marble is red. So

$P = P_{1} + P_{2} + P_{3} + P_{4} + P_{5} + P_{6} + P_{7} + P_{8}$

$P_{1}$ is the probability that we go R - R - R - R

There are 50 marbles, of which 30 are red. So, the probability of the first marble sorted being red is $\frac{30}{50} = \frac{3}{5}$ .

Now the red marble is returned to the bag, and another 3 red marbles are added.

Now there are 53 marbles, of which 33 are red. So, when the first marble sorted is red, the probability that the second is also red is $\frac{33}{53}$

Again, the red marble is returned to the bag, and another 3 red marbles are added

Now there are 56 marbles, of which 36 are red. So, in this sequence, the probability of the third marble sorted being red is $\frac{36}{56}$

Again, the red marble sorted is returned, and another 3 are added.

Now there are 59 marbles, of which 39 are red. So, in this sequence, the probability of the fourth marble sorted being red is $\frac{39}{59}$ . So

$P_{1} = \frac{3}{5}*\frac{33}{53}*\frac{36}{56}*\frac{39}{59} = \frac{138996}{875560} = 0.1588$

$P_{2}$ is the probability that we go R - R - B - R

$P_{2} = \frac{3}{5}*\frac{33}{53}*\frac{20}{56}*\frac{36}{61} = \frac{71280}{905240} = 0.0788$

$P_{3}$ is the probability that we go R - B - R - R

$P_{3} = \frac{3}{5}*\frac{20}{53}*\frac{33}{58}*\frac{36}{61} = \frac{71280}{937570} = 0.076$

$P_{4}$ is the probability that we go R - B - B - R

$P_{4} = \frac{3}{5}*\frac{20}{53}*\frac{25}{58}*\frac{33}{63} = \frac{49500}{968310} = 0.0511$

$P_{5}$ is the probability that we go B - R - R - R

$P_{5} = \frac{2}{5}*\frac{30}{55}*\frac{33}{58}*\frac{36}{61} = \frac{71280}{972950} = 0.0733$

$P_{6}$ is the probability that we go B - R - B - R

$P_{6} = \frac{2}{5}*\frac{30}{55}*\frac{25}{58}*\frac{33}{63} = \frac{49500}{1004850} = 0.0493$

$P_{7}$ is the probability that we go B - B - R - R

$P_{7} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{33}{63} = \frac{825}{17325} = 0.0476$

$P_{8}$ is the probability that we go B - B - B - R

$P_{8} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{30}{65} = \frac{750}{17875} = 0.0419$

So, the probability that this last marble is red is:

$P = P_{1} + P_{2} + P_{3} + P_{4} + P_{5} + P_{6} + P_{7} + P_{8} = 0.1588 + 0.0788 + 0.076 + 0.0511 + 0.0733 + 0.0493 + 0.0476 + 0.0419 = 0.5768$

There is a 57.68% probability that this last marble is red.

What's the probability that we actually drew the same marble all four times?

$P = P_{1} + P_{2}$

$P_{1}$ is the probability that we go R-R-R-R. It is the same $P_{1}$ from the previous item(the last marble being red). So $P_{1} = 0.1588$

$P_{2}$ is the probability that we go B-B-B-B. It is almost the same as $P_{8}$ in the previous exercise. The lone difference is that for the last marble we want it to be blue. There are 65 marbles, 35 of which are blue.

$P_{2} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{35}{65} = \frac{875}{17875} = 0.0490$

$P = P_{1} + P_{2} = 0.1588 + 0.0490 = 0.2078$

There is a 20.78% probability that we actually drew the same marble all four times

3 0

3 years ago

PLZZZZZZ HELP MARK BRAINIEST

MAXImum [283]

Answer:

a.J+J+10=M

b. 15+10=25M

c. 9-10=-1 9+(-1)=8

Step-by-step explanation:

8 0

2 years ago