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nlexa [21]
3 years ago
11

Slope is 5, (5,4) is on the line The equation of the line is y=

Mathematics
1 answer:
viktelen [127]3 years ago
6 0
Solve the equation 4= 5(5) + b
To get b
I got the equation by plugging in the slope and point into the y=Mx+b formula.
Hope this helps:)
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Make h the subject of the relation V=1/3πr²h
Elodia [21]

Answer:h=3V/πr^2

Step-by-step explanation:

V=1/3πr^2h

Cross multiply

3V=πr^2h

Divide both sides by πr^2

3V/πr^2=πr^2h/πr^2

3V/πr^2=h

h=3V/πr^2

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After 1 year, $300 deposited in a savings account with simple interest had earned $12 in
Eddi Din [679]

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4%

Step-by-step explanation:

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3 years ago
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Help please thank you
LenaWriter [7]

Answer:

B)60m^2

Step-by-step explanation:

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3 years ago
Mrs. Jones decided to buy some pencils for her class. She bought 3 packages of pencils, and each package contained 44 pencils. T
pantera1 [17]

Answer:

A

Step-by-step explanation:

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Then, divide 22 into 132. 132/22=6.

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Find the mass of the triangle with vertices (1; 0; 0), (0; 2; 0), (0; 1; 1) if the density function is given by (x; y; z)
Luda [366]

Answer:

=\frac{17}{3}

Step-by-step explanation:

Density of a function is \rho(x,y)=x^{2} +y^{2}

I have drawn the right angle triangle for visualization

equation for the line passing through (1,0) and (0,4) is

\frac{y}{4} =\frac{x-1}{-1}

y=4-4x

=$$\int_{0}^1\int_{0}^{4-4x} (x^{2}+y^{2})dydx$$

=$\int_{0}^{1}(x^{2}+\frac{y^{3} }{3})dx$  

=$\int_{0}^{1}(x^{2}(4-4x)+\frac{1}{3}(4-4x)^{3} )dx$

=$\int_{0}^{1}(\frac{-76}{3}x^{3} +68x^{2}-64x^{}+\frac{64}{3}  )dx$

==(\frac{-76}{3} \frac{x^{4} }{4})+\frac{68}{3}x^{3}-32x^{2}+\frac{64}{3}x^{})  

=\frac{17}{3}

3 0
3 years ago
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