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3 years ago

Slope is 5, (5,4) is on the line The equation of the line is y=

1 answer:

6 0

Solve the equation 4= 5(5) + b
To get b
I got the equation by plugging in the slope and point into the y=Mx+b formula.
Hope this helps:)

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What is the surface area of a mini basketball with a circumference.of 25 and radius of 4

Nonamiya [84]

The formula to find the surface area of a sphere is A=4(3.14)r². So if you plug in the data you would get,
A=4(3.14)4²
A=(12.56) (16)
A=200.96
You mught want to check over it so you will be able to solve it for yourself the next time you have this question.

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3 years ago

Please help me it would mean a lot thank you:)

Alexeev081 [22]

Number 4. will be a. because if you do 7*9=63*10=630.

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3 years ago

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What is the area of the shaded sector

Whitepunk [10]

Answer:

Area = 634.21 square metre

Step-by-step explanation:

Area of shaded region = Area of the circle - Area of the sector

$Area \ of \ the \ circle = \pi r^2 = 225 \pi\\\\Area \ of \ the \ sector = \pi r^2 \frac{ \theta}{360} = \pi \times 225 \times \frac{37}{360}$

$Area \ of \ shaded \ region = 225 \pi - (225 \pi \times \frac{37}{360})$

$= 225 \pi (1 - \frac{37}{360})\\\\= 225 \pi \times 0.89722\\\\=634.21 m^2$

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3 years ago

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The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$

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3 years ago

Which of the following shows 18,442 correctly rounded to the hundreds place?

svp [43]

Answer:

D)18,400

Step-by-step explanation:

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3 years ago

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