1.49 moles of Al will be produced. Hope this helps you.
We know that the element Z = 119 would be placed right below the Fr, in the column of the alcaline metals.
We also know that the trend in the electronegativity is to decrease when you go up-down ia group.
The known electronegativities of the elements of this group are:
Li: 0.98
Na: 0.93
K: 0.82
Rb: 0.82
Cs: 0.79
Fr: 0.70
Then the hypotetical element Z = 119 would probably have an electronegativity slightly below 0.70, for sure in the range 0.60 - 0.70.
Answer:
Explanation:
This question involves the conversion of mass into energy: E = mc².
e + p ⟶ γ + γ
Each particle has the same mass so, in terms of mass, we can write
2e ⟶ 2γ or
e ⟶ γ
Thus, we can just convert the mass of an electron to its energy equivalent.
(a) Energy in joules
(b) Energy in kilojoules per mole
(c) Energy in electron volts
<span>The </span>equilibrium<span> will </span>shift<span> to favor the side of the reaction that involves fewer moles of gas.
Its C
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<span> gallium arsenide (GaAs) and gallium phosphide (GaP)</span>