Answer:
2Ag(s) + 2HNO₃ (aq) → 2AgNO₃(aq) + H₂(g)
Explanation:
Metallic silver = Ag (s)
Concentrated nitric acid = HNO₃ (aq)
Product being hydrogen gas = H₂(g)
2Ag(s) + 2HNO₃ (aq) → 2AgNO₃(aq) + H₂(g)
Be careful AgNO₃ doesn't precipitate
Answer:
![[OH^-]=9.24x10^{-3}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D9.24x10%5E%7B-3%7DM)
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Explanation:
Hello,
In this case, since the ionization of methylamine is:
The equilibrium expression is:
![Kb=\frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BCH_3NH_3%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BCH_3NH_2%5D%7D)
And in terms of the reaction extent 
which is equal to the concentration of OH⁻ as well as that of CH₃NH₃⁺ via ice procedure we can write:
Whose solution for via quadratic equation is 9.24x10⁻³ M since the other solution is negative so it is avoided. Therefore, the concentration of OH⁻ is:
![[OH^-]=x=9.24x10^{-3}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3Dx%3D9.24x10%5E%7B-3%7DM)
With which we can compute the pOH at first:
![pOH=-log([OH^-])=-log(9.24x10^{-3})=2.034](https://tex.z-dn.net/?f=pOH%3D-log%28%5BOH%5E-%5D%29%3D-log%289.24x10%5E%7B-3%7D%29%3D2.034)
Then, since pH and pOH are related via:
The pH turns out:
Best regards.
Answer: A consultant dietians works in a health care facilities or they work in their own private practice under a contract.
Clinical dietians provide patients in places such as hospitals and nursing care facilities with medical nutrition and therapy.
Hope this helps.
Answer:
All of these oxides of manganese have a mass percent of metal greater than 50%
Explanation:
Step 1: Data given
Molar mass of Mn = 54.94 g/mol
Molar mass of O = 16 g/mol
<em><u>Step 2: Calculate mass % of Mn in MnO</u></em>
Molar mass of MnO = 54.94 + 16 = 70.94 g/mol
% Mn = (54.94/70.94)*100 % = 77.45 %
<u><em>Step 3: Calculate % of Mn in MnO2</em></u>
Molar mass of MnO2 = 54.94 + 2*16 = 86.94 g/mol
% Mn = (54.94/86.94) * 100% = 63.19 %
<u><em>Step 4: Calculate % of Mn in Mn2O3</em></u>
Molar mass of Mn2O3 = 2*54.94 + 3*16 = 157.88 g/mol
% Mn = ((2*54.94)/157.88)*100 % = 69.6 %
All of these oxides of manganese have a mass percent of metal greater than 50%
