Answer:
97.994 g/mol
Explanation:
One molecule of H₃PO₄ contains three atoms of H, one of P, and four of O.
3H = 3 × 1.0079 u = 3.0237 u
1P = 1 × 30.974 u = 30.974 u
4O = 4 × 15.999 u = <u>63.996 u
</u>
Total = 97.994 u
One molecule has a mass of 97.994 u.
One mole has a mass of 97.994 g.
The molar mass of H₃PO₄ is 97.994 g/mol.
Answer:
Explanation:
We must use the Nernst equation
Step 1. Calculate E°
SO₄²⁻(aq) + 4H⁺(aq) + 2e⁻ ⇌ SO₂(g) + 2H₂O(ℓ)
<u>2Br⁻⇌ Br₂(aq) + 2e⁻ </u>
SO₄²⁻(aq) + 4H⁺(aq) + 2Br⁻(aq) ⇌ Br₂(aq) + SO₂(g) + 2H₂O(ℓ)
E° = 0.17 - 1.0873 = -0.92 V
Step 2. Calculate Q
E = 0 V
E° = -0.92 V
R = 8.314 J·K⁻¹mol⁻¹
T = 66 °C
n = 2
F = 96 485 C/mol
Calculations:
T = 66.0 + 273.15 = 339.15 K
The correct term for each statement is as follows;
- Caves being formed by acid rain dissolving underground limestone - weathering
- Deltas forming at the mouths of rivers - deposition
- Glaciers scraping rocks across the earth’s surface - erosion
- Rocks being made smooth by tumbling across a stream bed - weathering
- Ponds filling up with sediment and becoming marshes - deposition
<h3>What is weathering?</h3>
Weathering in geology is the mechanical or chemical breaking down of rocks in situ by weather or other causes. options 7 and 14 are the case in this scenario as there is a breakdown of limestone and rocks.
Erosion is the result of having been worn away or eroded, as by a glacier on rock or the sea on a cliff face. Agents of erosion are water, ice or wind. Options 12 is an example of erosion because glaciers are wearing off rocks.
Deposition is the laying down of sediment carried by wind, flowing water, the sea or ice. Sediment can be transported as pebbles, sand and mud, or as salts dissolved in water. Options 8 and 15 are examples of deposition.
Learn more about weathering and deposition at: brainly.com/question/367069
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Answer:
1328 K or 1055 °C
Explanation:
To find the new temperature, you need to use the Combined Gas Law:
P₁V₁ / T₁ = P₂V₂ / T₂
In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature. After converting the temperature (T₁) from Celsius to Kelvin, you can plug the values into the equation and simplify.
P₁ = 1.0 atm P₂ = 0.90 atm
V₁ = 200 L V₂ = 1000 L
T₁ = 22 °C + 273.15 = 295.15 K T₂ = ? K
P₁V₁ / T₁ = P₂V₂ / T₂
(1.0 atm)(200 L) / 295.15 K = (0.90 atm)(1000 L) / T₂
0.6776 = (0.90 atm)(1000 L) / T₂
(0.6776) x T₂ = (0.90 atm)(1000 L)
(0.6776) x T₂ = 900
T₂ = 1328 K
T₂ = 1055 °C