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iragen [17]
3 years ago
14

Help asap plz its a test

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
4 0

Answer:

B

Explanation:

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A tank with a height of 100 feet and a constant cross sectional area of 10 ft has a constant input flow of 15 ft /hour of pulp s
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Answer:

(a) The consistency as a function of time is C=0.15*t.

(b) The tank will become clogged in 24 minutes.

Explanation:

The rate of accumulation of the pulp stock can be defined as

\frac{dC}{dt}=Q_{i}*C_{i}-Q_{o}*C_{o}

In this case, Co is 0, because the exit flow is only water and 0% fiber.

frac{dC}{dt}=Q_{i}*C_{i}-Q_{o}*0=Q_{i}*C_{i}

Rearranging adn integrating

dC = (Q_{i}*C_{i})dt\\\int dC = \int (Q_{i}*C_{i})dt\\C=(Q_{i}*C_{i})*t+constant

At t=0, C=0,

C=(Q_{i}*C_{i})*t+constant\\0=(Q_{i}*C_{i})*0+constant\\0=constant\\\\C=(Q_{i}*C_{i})*t

C=(15*0.01)*t=0.15*t

(b) The time at when the concentration reaches 6% is 0.4 hours or 24 minutes.

C=0.15*t\\0.06=0.15*t\\t=0.06/0.15=0.4

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