Answer:

Explanation:
Given
485 L
Required
Determine the measurement not equal to 485L

<em>From standard unit of conversion;</em>
1 KL = 1000 L
<em>Multiply both sides by 485</em>


<em>Divide both sides by 1000</em>

---- This is equivalent
---------------------------------------------------------------------------------------------

<em>From standard unit of conversion;</em>
1000 mL = 1 L
<em>Multiply both sides by 485</em>


Convert to standard form

Hence;
is not equivalent to 485L
---------------------------------------------------------------------------------------------

<em>From standard unit of conversion;</em>
100 cL = 1 L
<em>Multiply both sides by 485</em>


Convert to standard form
---- This is equivalent
---------------------------------------------------------------------------------------------
μL
<em>From standard unit of conversion;</em>
1000000 μL = 1 L
<em>Multiply both sides by 485</em>


Convert to standard form
---- This is equivalent
From the list of given options;
is not equivalent to 485L
1.54 x 10⁶kW
Explanation:
The problem here is converting from megawatts into kilowatts.
Given 1540megawatts.
The mega- and kilo- watts are prefixes that denotes multiples of units.
1 megawatt = 10⁶watts
1 kilowatt = 10³watts
Now given 1540megawatts power to Kilowatt power;
We see that :
1000kW = 1mW
1540mW x
= 1.54 x 10⁶kW
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Answer:
1.12×10¹¹ kg of CO₂ are produced with 4.6×10¹⁰ L of isooctane
Explanation:
Let's state the combustion reaction:
C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O
Let's calculate the mass of isooctane that reacts.
Density = Mass / Volume
Density . Volume = Mass
First of all, let's convert the volume in L to mL, so we can use density.
4.6×10¹⁰ L . 1000 mL / 1L = 4.6×10¹³ mL
0.792 g/mL . 4.6×10¹³ mL = 3.64 ×10¹³ g
This mass of isooctane reacts to produce CO₂ and water, so let's determine the moles of reaction
3.64 ×10¹³ g . 1mol / 114 g = 3.19×10¹¹ mol
Ratio is 1:8 so 1 mol of isooctane can produce 8 moles of dioxide
Therefore 3.19×10¹¹ mol would produce (3.19×10¹¹ mol . 8) = 2.55×10¹² moles of CO₂
Now, we can determine the mass of produced CO₂ by multipling:
moles . molar mass
2.55×10¹² mol . 44 g/mol = 1.12×10¹⁴ g of CO₂
If we convert to kg 1.12×10¹⁴ g / 1000 = 1.12×10¹¹ kg