Whats the difference between a solution and a compound? (sorry if this is funny to ask)

Chemistry

1 answer:

Kipish [7]3 years ago

3 0

Answer:

A compound is just pure that is composed of elements that are chemically bonded in definite proportions

andd solution is umm well its a homogenous so basically saying

that it all just stays the same all the way through

Explanation:

im not sure how else to explain it haah hope this helped :P

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Write a nuclear equation to describe the neutron induced fission of Pu-239 to form Kr-89 and Ce-149 (this fission is induced by

zlopas [31]

Answer:

$\rm 2_{0}^{1}\text{n} + \, _{94}^{239}\text{Pu} \longrightarrow_{36}^{89}\text{Kr} + \, _{58}^{149}\text{Ce} + \, 3_{0}^{1}\text{n}; three$

Explanation:

If the fission is induced by two neutrons, the unbalanced equation is

$2\rm _{0}^{1}\text{n} + \, _{94}^{239}\text{Pu} \longrightarrow_{36}^{89}\text{Kr} + \, _{58}^{149}\text{Ce} + \, x_{0}^{1}\text{n}$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation .

Balancing the superscripts, we get

2 + 239 = 89 + 149 + x

241 = 238 + x

x = 3

The balanced nuclear equation is

$\rm 2_{0}^{1}\text{n} + \, _{94}^{239}\text{Pu} \longrightarrow_{36}^{89}\text{Kr} + \, _{58}^{149}\text{Ce} + \, \mathbf{3}_{0}^{1}\text{n}$