Answer:
The prevalence of serious defects in this population at the time of birth is 10%.
Step-by-step explanation:
The prevalence of serious defects is the number of infants that were born with seriours birth defects divided by the total number of infants born.
In this problem, we have that:
There were 1000 newborn infants.
100 infants were born with serious birth defects.
Calculate the prevalence of serious defects in this population at the time of birth.
This is:

The prevalence of serious defects in this population at the time of birth is 10%.
Answer:120 units
Step-by-step explanation:
The answer is 12.5 seconds.
48/5 = 120/x
x = 2.5
2.5 * 5 = 12.5
Let

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

So, the base case is ok. Now, we need to assume
and prove
.
states that

Since we're assuming
, we can substitute the sum of the first n terms with their expression:

Which terminates the proof, since we showed that

as required
10 Inches
A = p q / 2
p = diagonal 1
q = diagonal 2
2A / q = p
Solve for p
180/18 = 10