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vampirchik [111]
3 years ago
9

Super fine 40-gauge copper wire has a diameter of only 0.080mm and weighs only 44.5/gkm . Suppose a spool of 40-gauge wire weigh

s 205.g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.
Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

Math expression=      L[m]=   W[g]   /   R[g/m]

answer=4.606Km

Step-by-step explanation:

It is known that the cable weighs 44kg / km therefore if the weight is divided by this amount we can find how much cable length was spent

L=W/R

L= leght of wire used(m)

W=weight used(g)=205g

R= relation between weight and leght(g/m)=44.5g/km=0.0445g/m

L=205g/0.0445g/m=  4606.74m=  4.606Km

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The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
\sqrt{( x_{2} - x_{1} ) ^{2} +( y_{2}- y_{1} ) ^{2}  }
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
\sqrt{(3-2) ^{2}+(4-3) ^{2}  }
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Now let's use the same formula to find out the length of one of the longer segments:
\sqrt{(5-3) ^{2} +(3-2) ^{2} }
which simplifies down to
\sqrt{(2) ^{2} +(1) ^{2} }
which is of course \sqrt{5}
Since we have 2 of those lengths, \sqrt{5} + \sqrt{5}=2 \sqrt{5}
So our perimeter is, in the end, 2 \sqrt{2}+2 \sqrt{5}
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