If 5.100 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final temp
1 answer:
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Answer:
0.2
Explanation:
Given parameters:
Mass of helium = 0.628g
Mass of neon = 11.491g
Mass of argon = 7.613g
Unknown:
Mole fraction of neon = ?
Solution:
The mole fraction of an element is the number of moles of that element to the total number of moles in the gas mixture.
We need to calculate the number of moles of each element first;
Number of moles =
Molar mass of Helium = 4g/mol
Molar mass of Neon = 20g/mol
Molar mass of Argon = 40g/mol
Number of moles of He = = 0.16moles
Number of moles of Ne = = 0.58moles
Number of moles of Ar = = 0.19moles
Total number of moles = 0.16moles + 0.58moles + 0.19moles = 0.93moles
Mole fraction Neon = = 0.2
Answer:
Explanation:
Given
Required
Calculate the number of moles
We'll apply the following formula to solve this question
Where
The above equation is an illustration of the ideal gas law
Substitute values for p, V, R and T in:
<em>Hence, there are 243.605 moles</em>
