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Vikentia [17]
3 years ago
11

20. How are photosynthesis and cellular respiration related? How are they different?

Chemistry
1 answer:
tino4ka555 [31]3 years ago
6 0
Photosynthesis makes the glucose that is used in cellular respiration to make atp. when photosynthesis requires carbon dioxide and releases oxygen, cellular respiration requires oxygen and releases carbon dioxide.
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What kind of reaction is shown below?
MatroZZZ [7]

Answer:

d. decomposition

Explanation:

decomposition reaction is a reaction in which a compound breaks down into 2 or more substances.

the general form is: AB → A + B

4 0
3 years ago
Do you really get 7 years of bad luck if you crack a mirror :(
Mazyrski [523]

Answer:

nope its a myth don't worry :)

4 0
2 years ago
List the subshells that hold the 25 electrons in a<br> manganese atom in order of increasing energy
jonny [76]

Answer:

1s2 2s2 2p6 3s2 3p6 4s2 3d5

Explanation:

According to the Aufbau principle, electrons are filled in orbitals in order of increasing energy. The energy of orbitals in the electronic configuration of manganese increases from left to right, hence 3d orbital is much greater in energy than a 3p orbital.

The arrangement of orbitals in order of increasing energy is shown in the answer above.

4 0
3 years ago
What does it mean for heat to be transferred by radiation?
iris [78.8K]

Answer:

Here's what I get  

Explanation:

It means that the heat comes directly at you without relying  on any material to conduct it.

For example, you feel the heat from a campfire even if the wind is blowing crosswise to you and the fire.

5 0
3 years ago
5. What concentration of acid must be added to change the pH of 1 mM phosphate buffer from 7.4 to 7.3 (pKas of the phosphate buf
mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and pK_{a} is as follows.

               pH = pK_{a} + log \frac{base}{acid}

where,     pH = 7.4 and pK_{a} = 7.21

As here, we can use the pK_{a} nearest to the desired pH.

So,      7.4 = 7.21 + log \frac{base}{acid}

             0.19 = log \frac{base}{acid}

            \frac{base}{acid} = 1.55

1 mM phosphate buffer means [HPO_{4}] + [H_{2}PO_{4}] = 1 mM

Therefore, the two equations will be as follows.

           \frac{HPO_{4}}{H_{2}PO_{4}} = 1.55 ............. (1)

  [HPO_{4}] + [H_{2}PO_{4}] = 1 mM ........... (2)        

Now, putting the value of [HPO_{4}] from equation (1) into equation (2) as follows.

             1.55[H_{2}PO_{4}] + [tex][H_{2}PO_{4}] = 1 mM

                        2.55 [H_{2}PO_{4}] = 1 mM

                             [H_{2}PO_{4}] = 0.392 mM

Putting the value of [H_{2}PO_{4}] in equation (1) we get the following.

                     0.392 mM + [HPO_{4}] = 1 mM

                          [HPO_{4}] = (1 - 0.392) mM

                              [HPO_{4}] = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0
3 years ago
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