<u>Answer:</u> The number of moles of weak acid is
moles.
<u>Explanation:</u>
To calculate the moles of KOH, we use the equation:
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We are given:
Volume of solution = 43.81 mL = 0.04381 L (Conversion factor: 1L = 1000 mL)
Molarity of the solution = 0.0969 moles/ L
Putting values in above equation, we get:

The chemical reaction of weak monoprotic acid and KOH follows the equation:

By Stoichiometry of the reaction:
1 mole of KOH reacts with 1 mole of weak monoprotic acid.
So,
of KOH will react with =
of weak monoprotic acid.
Hence, the number of moles of weak acid is
moles.
Answer:
2N2 + O2 ⇒ 2N2O
Explanation:
Since I cannot see the product's of the second chemical equation I will only solve the first one.
In order to balance a chemical equation you need to make sure that the atoms on both sides are equal.
In this case we have...
N2 + O2 = N2O
N = 2
O = 2
N = 2
O = 2
Change the coefficient:
N2O = 2N20
2 × 2 = 4
1 × 2 = 2
2N2 + O2 ⇒ 2N2O
Hope this helps.
Explanation:
In the context, a vial which is used in store medical samples is filled with water at room temperature. And the vial is kept on a cold water. Also a water bag containing warm water is kept near the vial.
The cold water kept at the bottom of the vial is having lower kinetic energy while warm water will have higher kinetic energy than the others. Since the water in the vial is at room temperature and it is in touch with the cold blue water, the water in the vial will loose or give its temperature to the cold blue water through conduction as well as convection process since temperature always flows from a hot body towards the cold body.
On the other hand, the warm water placed next tot he vial will give its temperature to the atmosphere.
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<u>Volume </u><u>of</u><u> 106.9 mL from the concentrated solution should be taken and diluted to 350 </u><u>mL.</u>
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<u>Main I'd On Indian Brainly Is - HeartCrush</u>
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<u>We can use the </u><u>formula.</u><u> </u>
c1v1 =c2v2
<u>Where c1 is the concentration and v1 is volume of the concentrated </u><u>solution.</u><u> </u>
c2 is the concentration
and v2 is the volume of the diluted solution to be prepared
9.00 M x V1 = 2.75 M x 350 mL
V1 = 106.9 mL
<u>Volume of 106.9 mL from the concentrated solution should be taken and diluted to 350 </u><u>mL</u><u>.</u>