Indicator species may provide useful substitute for large scale surveys to monitor biodiversity. Weconducted surveys in the Afro-alpine habitats of the Bale Mountains National Park (BMNP) with theobjective of identifying indicators for the species richness of the raptor guild. Raptors were countedby scan sampling technique from a suitable vintage point. Three classes of 18 sample units groupedaccording to the variability of the moorland ecosystem in the magnitude of process variables importantfor raptor species richness were used in determining the indicator value of species as a function of their abundance concentration and the percentage of species occurrence per sample group. Thisprocedure determined indicator values for all species in the resident raptor community. Comparisonwith randomly expected values demonstrated that only<span> Aquila verreauxii</span>and<span> A. chrysaetos</span>haveindicator values that were significantly larger than the randomly expected values. The species richnessestimated using the abundances of these two species predicted the observed species richness of thewhole community in a linear regression model that explained 66% of the deviance in the data set.Furthermore, the species richness of the community predicted by process variables had correlation of very high significance with that predicted by the indicator species. We have thus identified twoindicator species to a raptor guild of the BMNP and demonstrated that these two species encapsulatedmost of the information regarding the species richness response of the guild to key process variablesin the Afro-alpine moorland ecosystem. Our findings contribute significantly to current and futureefforts of monitoring the biodiversity of the park providing a cheap and quick means of data generation<span>relevant for making management decisions. Hope this helped! :)</span>
C) <em>The frequency of heterozygotes is given by (p + q)/N, where N is the number of individuals in the population.</em>
Answer:
Joan Walks
miles farther than maria
Explanation:
Given:
Distance walked by Nicole = 1. 11/12 miles
Distance walked by Tasha= 2. 1/12 miles
Distance walked by Maria = 1. 7 /12 miles
Distance walked by Joan = 2. 2/12 miles
To find:
How much farther Joan walks to school than Maria = ?
Solution:
We can find the distance that Joan walk more than maria by subtraction
Joan distance - maria distance
here the distance are given in mixed fraction , so lets covert them into fraction and perform subtraction
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<span>They were produced by recombinant DNA technology. </span>
One of the most commonly used methods of analysing the age of a certain crust is through analysis of its isotropic composition, such as the presence of the elements of tellurium and selenium. However, by general principle, the continental crusts are considered to be much older than the oceanic crusts.