According to Balance chemical equation,
N₂ + 3 H₂ → 2 NH₃
1 mole of Nitrogen reacts with 3 moles of Hydrogen to produce 2 mole of Ammonia.
It is known that i mole of any gas at standard temperature and pressure occupies 22.4 L of Volume. So, we can also say,
22.4 L (1 × 22.4) of Nitrogen gas (in question it is taken in excess) reacts with 67.2 L (22.4 × 3) of Hydrogen gas to produce 44.8 L (22.4 × 2) of Ammonia.
Result:
44.8 L is the correct answer.
Answer:
6l
Explanation: convert temperature to kelvin by adding 273 and then input the values into the formula with the given constant
2*v=0.5*0.8206*288 then divide both sides by 2 and get the amount in litres which is 6
When we have Ksp CaSO4 = 9.1x10^-6 so by substitution in Ksp formula:
Ksp CaSO4 = [Ca+2][SO4]
1.9x10^-6 = [Ca+2][1.5x10^-2]
∴ [Ca+2] M in the solution =1.27x10^-4
when percent remaining = [Ca in solution]/[C original value] * 100
= [(1.27x10^-4*(50ml+50ml)]/[1.28x10^-2*50ml]*100
≈ 2%
% mass Na = (g Na / g H2O) x 100
<span>g Na = (% mass Na)(g H2O) / 100 = (5.2 x 10^-4 g Na / g H2O) </span>
<span>2.4 g Na x (1 g H2O / 5.2 x 10^-4 g Na) = 4600 g Na </span>
<span>4600 g Na x (1 mL H2O / 1 g H2O) = 4600 mL H2O = 4.6 L H2O which is a little more than a gallon</span>
