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3 years ago

What is the volume of 0.5 moles of a gas at 2 atmospheres of pressure and 15°c

Chemistry

1 answer:

liq [111]3 years ago

4 0

Answer:

Explanation: convert temperature to kelvin by adding 273 and then input the values into the formula with the given constant

2*v=0.5*0.8206*288 then divide both sides by 2 and get the amount in litres which is 6

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Xian drew a diagram to compare deletion mutations and substitution mutations. Which label belongs in the area marked "X"? may ch

tankabanditka [31]

Answer: (B)

Explanation: Decreases the number of bases in the sequence.

3 0

3 years ago

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A flexible container at an initial volume of 6.13 L contains 2.51 mol of gas. More gas is then added to the container until it r

aleksley [76]

Answer:

2.12 moles of gas were added.

Explanation:

We can solve this problem by using Avogadro's law, which states that at constant temperature and pressure:

V₁n₂=V₂n₁

Where in this case:

V₁ = 6.13 L

n₂ = ?

V₂ = 11.3 L

n₁ = 2.51 mol

We input the data:

6.13 L * n₂ = 11.3 L * 2.51 mol

n₂ = 4.63

As 4.63 moles is the final number of moles, the number of moles added is:

4.63 - 2.51 = 2.12 moles

5 0

3 years ago

You determine the volume of your plastic bag (simulated human stomach) is 1.08 L. How many grams of NaHCO3 (s) are required to f

dsp73

Answer:

3.636 grams of sodium bicarbonate is required.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 753.5 mmHg = 0.9914 atm

( $1 atm = 760 mmHg$ )

V = Volume of gas = 1.08 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 24.5 °C= 297.65 K

Putting values in above equation, we get:

$(0.9914 atm)\times 1.08 L=n\times (0.0821L.atm/mol.K)\times 297.65K\\\\n=0.0438 mole$

Percentage recovery of carbon dioxide gas = 49.4%

Actual moles of carbon dioxide formed: 49.4% of 0.0438 mole

$\frac{49.4}{100}\times 0.0438 mol=0.02164 mol$

$2NaHCO_3\righarrow Na_2CO_3+H_2O+CO_2$

According to reaction ,1 mol is obtained from 2 moles of sodium bicarbonate.

Then 0.02164 moles f carbon dioxide will be obtained from:

$\frac{2}{1}\times 0.02164 mol=0.04328 mol$

Mass of 0.04328 moles pf sodium bicarbonate:

0.04328 mol × 84 g/mol = 3.636 g

3.636 grams of sodium bicarbonate is required.

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4 years ago

The element copper has naturally occurring isotopes with mass numbers of 63 and 65. The relative abundance and atomic masses are

timofeeve [1]

Answer:

63.546

Explanation:

The Average atomic mass is calculated using the formula:

sum of the product of the atomic masses and their relative abundances all divided by 100 or total abundance

4 0

3 years ago

How would you prepare 100.0 ml of.400 m CaCl2 from a stock solution of 2.00 M CaCl2?

docker41 [41]

C₀=2 mol/l
c₁=0.400 mol/l
v₁=100.0 ml = 0.1 l

c₁v₁=c₀v₀

v₀=c₁v₁/c₀
v(H₂O)=v₁-v₀

v₀=0.1*0.400/2=0.02 l = 20 ml
v(H₂O)=100 - 20 = 80 ml

It is necessary to mix 20 ml of the feed solution and 80 ml of water.

4 0

3 years ago

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What is the volume of 0.5 moles of a gas at 2 atmospheres of pressure and 15°c​

What is the volume of 0.5 moles of a gas at 2 atmospheres of pressure and 15°c