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3 years ago

8

The sugar ribose is an important component of RNA. Ribose is 40.0% C, 6.7% H, and 53.3\% by mass. How many grams of each element

are present in a 50 g sample of ribose?

1 answer:

Brums [2.3K]3 years ago

5 0

Answer:

C_5H_10O_5

Explanation:

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Why is photosynthesis an example of chemical change, and why is it classified as endothermic?

Alexeev081 [22]

Answer:

It is an example of chemical reaction because carbon dioxide and water are converted into glucose and oxygen. If that makes any sense. and it is classified as endothermic because it requires the input of energy in the form of solar energy.

Explanation:

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3 years ago

PLEASE HELP! I DONT KNOW WHAT TO DO! ITS ALOT PLEASE HELP THO!

kirza4 [7]

Answer:

CuCl2 (aq) + (NH4)2CO3(aq) → NH4Cl(aq) + CuCO3(s)

* CuCl2 (aq) + (NH4)2CO3(aq) → 2NH4Cl(aq) + CuCO3(s)

*Cu(2+)(aq)+ 2Cl(-)(aq) + 2NH4(+)(aq) + CO3(2-)(aq) →2NH4(+)(aq) + Cl(-)(aq) + CuCO3(s)

*Cu(2+)(aq)+ CO3(2-)(aq) → CuCO3(s)

*2HCl(aq) + 2MgCO3(s) → 2MgCl(aq) + H2O(l) + 2CO2(g)

* 2H(+)(aq) + 2Cl(-)(aq) + 2MgCO3(s) → 2Mg(2+)(aq) +2Cl(-) (aq) + H2O(l) + 2CO2(g)

* 2MgCO3(s) → 2Mg(2+)(aq) + H2O(l) + 2CO2(g)

*ZnCl2(aq) + 2AgC2H3O2(aq) → 2AgCl(s) + Zn(C2H3O2)2(aq)

*Zn(2+)(aq) + 2Cl(-)(aq) + 2Ag(+)(aq) + C2H3O2(-)(aq) → 2AgCl(s) + Zn(2+)(aq) 2C2H3O2(-)(aq)

*2Cl(-)(aq) + 2Ag(+)(aq) → 2AgCl(s)

*MnO(s) + H2SO4(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*FeS(s) + 2HCl (aq) → FeCl2(aq) + H2S(g)

*FeS(s) + 2H(+)(aq) + 2Cl(-)(aq) → Fe(2+)(aq)+ 2Cl(-)(aq)) + H2S(g)

*FeS(s) + 2H(+)(aq) → Fe(2+)(aq)+ H2S(g)

Explanation:

In the first equation you only need to know the rules of solubility. All chlorides are solubles except Ag+ Pb+2 and Hg2(2+) and most carbonates are insolubles

<em>For ionic equations</em> Start with a balanced molecular equation. Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions indicate the correct formula and charge of each ion . Indicate the correct number of each ion and write (aq) after each ion . Bring down all compounds with (s), (l), or (g) unchanged.

<em>For net ionic equations </em>Write the balanced molecular equation. Write the balanced complete ionic equation. Cross out the spectator ions that are present. Write the "leftovers" as the net ionic equation.

Before this, te equation must be balanced.

* CuCl2 (aq) + (NH4)2CO3(aq) → 2NH4Cl(aq) + CuCO3(s)

*Cu(2+)(aq)+ 2Cl(-)(aq) + 2NH4(+)(aq) + CO3(2-)(aq) →2NH4(+)(aq) + Cl(-)(aq) + CuCO3(s)

*Cu(2+)(aq)+ CO3(2-)(aq) → CuCO3(s)

*2HCl(aq) + 2MgCO3(s) → 2MgCl(aq) + H2O(l) + 2CO2(g)

* 2H(+)(aq) + 2Cl(-)(aq) + 2MgCO3(s) → 2Mg(2+)(aq) +2Cl(-) (aq) + H2O(l) + 2CO2(g)

* 2MgCO3(s) → 2Mg(2+)(aq) + H2O(l) + 2CO2(g)

*ZnCl2(aq) + 2AgC2H3O2(aq) → 2AgCl(s) + Zn(C2H3O2)2(aq)

*Zn(2+)(aq) + 2Cl(-)(aq) + 2Ag(+)(aq) + C2H3O2(-)(aq) → 2AgCl(s) + Zn(2+)(aq) 2C2H3O2(-)(aq)

*2Cl(-)(aq) + 2Ag(+)(aq) → 2AgCl(s)

*MnO(s) + H2SO4(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*FeS(s) + 2HCl (aq) → FeCl2(aq) + H2S(g)

*FeS(s) + 2H(+)(aq) + 2Cl(-)(aq) → Fe(2+)(aq)+ 2Cl(-)(aq)) + H2S(g)

*FeS(s) + 2H(+)(aq) → Fe(2+)(aq)+ H2S(g)

7 0

3 years ago

The space shuttle___.

Len [333]

Answer:

goes very fast and carries astronauts

Explanation:

5 0

3 years ago

Help please I need it bad

natta225 [31]

= 9.1 × 10^6
(scientific notation)

= 9.1e6
(scientific e notation)

= 9.1 × 10^6
(engineering notation)
(million; prefix mega- (M))

= 9100000
<span>(real number)</span>

5 0

3 years ago

In Part III, the phenolphthalein indicator is used to monitor the equilibrium shifts of the ammonia/ammonium ion system. The phe

AnnZ [28]

The pink color in the solution fades. Some of the colored indicator ion converts to the colorless indicator molecule.

<h3>Explanation</h3>

What's the initial color of the solution?

$\text{NH}_4\text{Cl}$ is a salt soluble in water. $\text{NH}_4\text{Cl}$ dissociates into ions completely when dissolved.

$\text{NH}_4\text{Cl} \; (aq)\to {\text{NH}_4}^{+} \; (aq) +{\text{Cl}}^{-} \; (aq)$ .

The first test tube used to contain $\text{NH}_4\text{OH}$ . $\text{NH}_4\text{OH}$ is a weak base that dissociates partially in water.

$\text{NH}_4\text{OH} \; (aq) \rightleftharpoons {\text{NH}_4}^{+} \;(aq)+ {\text{OH}}^{-} \; (aq)$ .

There's also an equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$ .

$\text{OH}^{-}$ ions from $\text{NH}_4\text{OH}$ will shift the equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ to the right and reduce the amount of ${\text{H}_3\text{O}}^{+}$ in the solution.

The indicator equilibrium will shift to the right to produce more ${\text{H}_3\text{O}}^{+}$ ions along with the colored indicator ions. The solution will show a pink color.

What's the color of the solution after adding NH₄Cl?

Adding $\text{NH}_4\text{Cl}$ will add to the concentration of ${\text{NH}_4}^{+}$ ions in the solution. Some of the ${\text{NH}_4}^{+}$ ions will combine with $\text{OH}^{-}$ ions to produce $\text{NH}_4\text{OH}$ .

The equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions will shift to the left to produce more of both ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$

The indicator equilibrium will shift to the left as the concentration of ${\text{H}_3\text{O}}^{+}$ increases. There will be less colored ions and more colorless molecules in the test tube. The pink color will fade.

7 0

3 years ago