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3 years ago

8

The sugar ribose is an important component of RNA. Ribose is 40.0% C, 6.7% H, and 53.3\% by mass. How many grams of each element

are present in a 50 g sample of ribose?

1 answer:

Brums [2.3K]3 years ago

5 0

Answer:

C_5H_10O_5

Explanation:

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What is the chemical formula for decomposition?

shutvik [7]

Answer: AB A + B

Explanation:

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3 years ago

Which reaction represents the process of neutralization? Mg(s)+2HCl(aq) MgCl 2 (aq)+H 2 (g) HCl(aq)+KOH(aq) KCl(aq)+H 2 O(l) C.

Alex

Answer:

HCl(aq) + KOH(aq) --> KCl(aq) + H2O(l)

Explanation:

A neutralization reaction is the process between an acid and a base (there are a number of different ways to define acids and bases). An acid is a compound, which dissolves in water by releasing H+ ions, and a base is a compound, which dissolves in water by releasing OH- ions (by Arrhenius' definition, the simplest one). In this case, the neutralization reaction is the process between HCl (hydrochloric acid) - an acid, and KOH (potassium hydroxide) - a base.

7 0

3 years ago

Which of the following best describes regolith?

almond37 [142]

A. <span>the layer of rock and mineral fragments that covers nearly all of Earth's land surface</span>

8 0

3 years ago

Read 2 more answers

What is the mass of 1.2 x 1023 atoms of arsenic?

Gre4nikov [31]

Answer:

14.93 g

Explanation:

First we <u>convert 1.2 x 10²³ atoms of arsenic (As) into moles</u>, using <em>Avogadro's number</em>:

1.2 x 10²³ atoms ÷ 6.023x10²³ atoms/mol = 0.199 mol As

Then we can<u> calculate the mass of 0.199 moles of arsenic</u>, using its<em> molar mass</em>:

0.199 mol * 74.92 g/mol = 14.93 g

Thus, 1.2x10²³ atoms of arsenic weigh 14.93 grams.

6 0

3 years ago

A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a

Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$q=mc\Delta T$

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

$q_{released}=q_{absorbed}\\
q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T$

The given mass of calorimeter has been, $m_{calorimeter}=1350\;\rm g$

The specific heat of the calorimeter has been, $c_{calorimeter}=5.82\;\rm J/g^\circ C$

The change in temperature of the calorimeter has been, $\Delta T=2.87^\circ \rm C$

Substituting the values for heat released:

$q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\
q_{released}=22,549.5\;\text J\\
q_{released}}=22.54\;\rm kJ$

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0

2 years ago