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vlada-n [284]
3 years ago
11

Water softeners often replace calcium ions in hard water with sodium ions. since sodium compounds are soluble, the presence of s

odium ions in water does not result in the white, scaly residues caused by calcium ions. however, calcium is more beneficial to human health than sodium. calcium is a necessary part of the human diet, while high levels of sodium intake are linked to increases in blood pressure. the food and drug administration (fda) recommends that adults ingest less than 2.4 g of sodium per day. part a how many liters of softened water, containing a sodium concentration of 0.035 % sodium by mass, have to be consumed to exceed the fda recommendation? (assume a density of 1.0 g/ml for water.)
Chemistry
1 answer:
Mamont248 [21]3 years ago
6 0
% mass Na = (g Na / g H2O) x 100 
<span>g Na = (% mass Na)(g H2O) / 100 = (5.2 x 10^-4 g Na / g H2O) </span>

<span>2.4 g Na x (1 g H2O / 5.2 x 10^-4 g Na) = 4600 g Na </span>

<span>4600 g Na x (1 mL H2O / 1 g H2O) = 4600 mL H2O = 4.6 L H2O which is a little more than a gallon</span>
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Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO2H) and 0.230 mol of sodium formate (NaCO2H)
Veronika [31]

The question is incomplete, here is the complete question:

Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO₂H) and 0.230 mol of sodium formate (NaCO₂H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.77 × 10⁻⁴

a) 2.099

b) 10.463

c) 3.546

d) 2.307

e) 3.952

<u>Answer:</u> The pH of the solution is 3.546

<u>Explanation:</u>

We are given:

Moles of formic acid = 0.370 moles

Moles of sodium formate = 0.230 moles

Volume of solution = 1 L

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:  

pH=pK_a+\log(\frac{[salt]}{[acid]})

pH=pK_a+\log(\frac{[HCOONa]}{[HCOOH]})

pK_a = negative logarithm of acid dissociation constant of formic acid = 3.75

[HCOONa]=\frac{0.230}{1}  

[HCOOH]=\frac{0.370}{1}

pH = ?  

Putting values in above equation, we get:  

pH=3.75+\log(\frac{0.23/1}{0.37/1})\\\\pH=3.54

Hence, the pH of the solution is 3.546

5 0
3 years ago
ii. Use the solubility table to label the state symbols of each compound in the reaction. (1 point) AgNO3 + KCL = AgCl + KNO3
rjkz [21]

Answer:

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Explanation:

In a <em>solubility table</em> you find:

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In a chemical equation the states of soluble compounds is identified as aqeous, using the letter "aq" in parenthesis, and the state of insoluble compounds is identified as solid, using "s" in parenthesis.

Then, the reaction showing the states of the reactants and products is:

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olchik [2.2K]

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