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Mkey [24]
3 years ago
7

What is the structural formula for the following Molecules?

Chemistry
1 answer:
topjm [15]3 years ago
4 0

Answer:

Explanation:

1. The molecular formula for water is H2O. One molecule of water consists of one oxygen atom covalently bonded to two hydrogen atoms

2.The chemical formula of ammonia is NH3, and its molar mass is 17.03 g/mol. The ammonia molecule has a trigonal pyramidal shape, with nitrogen connected to the three hydrogen atoms. The nitrogen atom has a lone electron pair, which makes ammonia a base.

3.The chemical formula of ammonia is NH3, and its molar mass is 17.03 g/mol. The ammonia molecule has a trigonal pyramidal shape, with nitrogen connected to the three hydrogen atoms. The nitrogen atom has a lone electron pair, which makes ammonia a base.

4.the chemical structure of chlorine gas is Cl2 and its molecular weight is 70 g/mol. Its structure is Cl-Cl, which is also called the element form of the chlorine element, consist in 2 atoms of chlorine joined by a covalent bond.

5.Ethane is a colorless, odorless, and flammable gas with a chemical formula of C2H6; it has two carbon (C) atoms and six hydrogen (H) atoms. It's only composed of carbon and hydrogen atoms, so it is classified as a hydrocarbon.

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The concentration of reactants and products and the rate of reaction were measured during a chemical reaction. After the first 3
igomit [66]

Answer: B

Explanation:

4 0
2 years ago
Determine the number of moles of gas in a 4.1L container at 341K with a pressure of 1.78 atm.
lozanna [386]

Answer:

0.26 mol

Explanation:

using general gas equation

PV=nRT

V=4.1litre= 4.1 dm³

P= 1.78 atm

R= 0.0821

PUT VALUES

8 0
3 years ago
A 25.0 L tank of nitrogen gas is at 25 oC and 2.05 atm . If the temperature stays at 25 oC and the volume is decreased to 14.5 L
NeTakaya

Answer:

\boxed {\boxed {\sf P_2 \approx 3.53 \ atm}}

Explanation:

In this problem, the temperature stays constant. The volume and pressure change, so we use Boyle's Law. This states that the pressure of a gas is inversely proportional to the volume. The formula is:

P_1V_1=P_2V_2

Now we can substitute any known values into the formula.

Originally, the gas has a volume of 25.0 liters and a pressure of 2.05 atmospheres.

25.0 \ L * 2.05 \ atm = P_2V_2

The volume is decreased to 14.5 liters, but the pressure is unknown.

25.0 \ L * 2.05 \ atm = P_2 * 14.5 \ L

Since we are solving for the new pressure, or P₂, we must isolate the variable. It is being multiplied by 14.5 liters and the inverse of multiplication is division. Divide both sides by 14.5 L .

\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}=\frac{P_2 *14.5 \ L}{14.5 \ L}

\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}= P_2

The units of liters cancel.

\frac {25.0  * 2.05 \ atm }{14.5 }=P_2

\frac {50.25\  atm }{14.5 }=P_2

3.53448276 \ atm = P_2

The original values of volume and pressure have 3 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 3.53448276

The 4 in the thousandth place (in bold above) tells us to leave the 3 in the hundredth place.

3.53 \ atm \approx P_2

The new pressure is approximately <u>3.53 atmospheres.</u>

8 0
3 years ago
True or false. adding more neutrons to a neutrally charged atom will not change the charge
san4es73 [151]
The statement is true.
6 0
4 years ago
Determine the resulting pH when 12mL if 0.16M HCl are reacted with 32 mL if 0.24M KOH.
TEA [102]

Answer:

pH = 13.1

Explanation:

Hello there!

In this case, according to the given information, we can set up the following equation:

HCl+KOH\rightarrow KCl+H_2O

Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:

n_{HCl}=0.012L*0.16mol/L=0.00192mol\\\\n_{KOH}=0.032L*0.24mol/L=0.00768mol

Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:

n_{KOH}=0.00768mol-0.00192mol=0.00576mol

And the resulting concentration of KOH and OH ions as this is a strong base:

[KOH]=[OH^-]=\frac{0.00576mol}{0.012L+0.032L}=0.131M

And the resulting pH is:

pH=14+log(0.131)\\\\pH=13.1

Regards!

3 0
3 years ago
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