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Rudiy27
3 years ago
7

Determine the number of moles of gas in a 4.1L container at 341K with a pressure of 1.78 atm.

Chemistry
1 answer:
lozanna [386]3 years ago
8 0

Answer:

0.26 mol

Explanation:

using general gas equation

PV=nRT

V=4.1litre= 4.1 dm³

P= 1.78 atm

R= 0.0821

PUT VALUES

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<h3>Answer:</h3>

            Empirical Formula  =  C₃H₈O₃

            Molecular Formula  =  C₃H₈O₃

<h3>Solution:</h3>

Data Given:

                      Mass of Sample  =  9.2 g

                      Mass of Carbon  =  3.6 g

                      Mass of Hydrogen  =  0.8 g

                      Mass of Oxygen  =  9.2 - (3.6 + 0.8) = 4.8 g

Step 1: Calculate Moles of each Element;

                      Moles of C  =  Mass of C ÷ At.Mass of C

                      Moles of C  = 3.6 ÷ 12.01

                      Moles of C  =  0.2997 mol


                      Moles of H  =  Mass of H ÷ At.Mass of H

                      Moles of H  = 0.8 ÷ 1.01

                      Moles of H  =  0.7920 mol


                      Moles of O  =  Mass of O ÷ At.Mass of O

                      Moles of O  = 4.8 ÷ 16.0

                      Moles of O  =  0.3000 mol

Step 2: Find out mole ratio and simplify it;

                C                                        H                                     O

            0.2997                              0.7920                           0.3000

    0.2997/0.2997                  0.7920/0.2997              0.3000/0.2997

               1                                      2.64                                    1.001

Multiply by 3,

               3                               7.92 ≈ 8                                    3

Hence,  Empirical Formula  =  C₃H₈O₃

Step 3: Calculating Molecular Formula:

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  92 g.mol⁻¹

Empirical Formula Weight  =  12 (C₃) + 1.01 (H₈) + 16 (O₃)  =  92.08 g.mol⁻¹

So,

                     n  =  92 g.mol⁻¹ ÷ 92 g.mol⁻¹

                     n  =  1

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 1 × C₃H₈O₃

                    Molecular Formula  =  C₃H₈O₃

7 0
3 years ago
A gas that has a volume of 28 liters, a temperature of 45 °C, and an unknown pressure has its volume increased
allochka39001 [22]

Answer:

2.5 atm

Explanation:

V1 = 28L

T1 = 45°C = (45 + 273.15)K = 318.15K

V2 = 34L

T2 = 35°C = (35 + 273.15)K = 308.15k

P2 = 2.0atm

P1 = ?

From general gas equation,

(P1 × V1) / T1 = (P2 × V2) / T2

P2 × V2 × T1 = P1 × V1 × T2

P1 = (P2 × V2 × T1) / (V1 × T2)

P1 = (2.0 × 34 × 318.15) / (28 × 308.15)

P1 = 21634.5 / 8628.2

P1 = 2.5 atm

The initial pressure of the gas is 2.5atm

5 0
3 years ago
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