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Answer:
The camera would flow the same velocity and acceleration of the droplet until 9ft. After that it would switch gear and accelerate back to its original spot at the rate of 140.54 m/s2 in order to catch the next droplet.
Explanation:
The time it takes for the drop to reach 7-ft and 9-ft at the acceleration of 32.2ft/s2:
When s = 7ft,
When s = 9ft,
So it would take Δt = 0.75 - 0.66 = 0.09 s for each drop to travel from 7ft to 9ft. As the drops are released every 0.5s, this means that after our cam follow the first drop to the end of the 7-9ft window, it has 0.5 - 0.09 = 0.41 s or less to reverse its acceleration and go back to the original spot to take care of the next drop.
So at 9ft, the drop and camera velocity would be:
So if the camera reverses its direction to go back to original spot at the rate of a (ft/s2) and initial speed of 24.1 ft/s. Within the time span of 0.41s to catch the next drop at 7ft
So the camera would flow the same velocity and acceleration of the droplet until 9ft. After that it would switch gear and accelerate back to its original spot at the rate of 140.54 m/s2 in order to catch the next droplet.
Answer:
Context
Explanation:
It is of great value for an engineer to keep the context of his/her experiment in mind.
Answer:
763.94Wh
Explanation:
If the load is 120 watts running for 4 hours per night, the energy consumed is
120*4 =480 Wh
So, the energy gathered by the PV array is
E=480/(77%*96%*85%)=763.94Wh
Answer:
The capacity of the sludge pump is 0.217 m3/min
Explanation:
Solution is attached below