Answer:
goodman = 0.694
life of beam = 211597
Explanation:
alternating stress = 48 kpsi
mean stress = 24 kpsi
ultimate strength = 100 kpsi
endurance limit = 40 kpsi
goodman:
= ![\frac{mean stress}{ultimate stress} +\frac{alternating stress}{endurance limit} =\frac{1}{N}](https://tex.z-dn.net/?f=%5Cfrac%7Bmean%20stress%7D%7Bultimate%20stress%7D%20%2B%5Cfrac%7Balternating%20stress%7D%7Bendurance%20limit%7D%20%3D%5Cfrac%7B1%7D%7BN%7D)
= ![\frac{24}{100} +\frac{48}{40} =\frac{1}{N}](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7B100%7D%20%2B%5Cfrac%7B48%7D%7B40%7D%20%3D%5Cfrac%7B1%7D%7BN%7D)
= 0.24 + 1.2 = ![\frac{1}{N}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BN%7D)
N = 1/1.44
N = 0.694
2. check attachment for diagram
Log(N)-3/3 = log90 - log48/log90 - log40
Log(N)-3/3 = 0.77517
Log N = 5.325509
N = 10^(5.325509)
N = 211597
Answer:
(a) The velocity of the collar = 1.624er-15.54eo in/s
(b) the acceleration of the collar=-49.94er-9.74eo in/s²
(c)the acceleration of collative rod =-3.284er in/s²
Explanation:
Check attachment for calculation
Answer:
Rate of heat transfer to the room air per meter of pipe length equals 521.99 W/m
Explanation:
Since it is given that the radiation losses from the pipe are negligible thus the only mode of heat transfer will be by convection.
We know that heat transfer by convection is given by
![\dot{Q}=hA(T-T_{\infty })](https://tex.z-dn.net/?f=%5Cdot%7BQ%7D%3DhA%28T-T_%7B%5Cinfty%20%7D%29)
where,
h = heat transfer coefficient = 10.45
(free convection in air)
A = Surface Area of the pipe
Applying the given values in the above formula we get
![\dot{Q}=10.45\times \pi DL\times (130+273-(24+273))\\\\\frac{\dot{Q}}{L}=10.45\times 0.15\times \pi \times (130-24)\\\\\frac{\dot{Q}}{L}=521.99W/m](https://tex.z-dn.net/?f=%5Cdot%7BQ%7D%3D10.45%5Ctimes%20%5Cpi%20DL%5Ctimes%20%28130%2B273-%2824%2B273%29%29%5C%5C%5C%5C%5Cfrac%7B%5Cdot%7BQ%7D%7D%7BL%7D%3D10.45%5Ctimes%200.15%5Ctimes%20%5Cpi%20%5Ctimes%20%28130-24%29%5C%5C%5C%5C%5Cfrac%7B%5Cdot%7BQ%7D%7D%7BL%7D%3D521.99W%2Fm)
Answer:
The drying time is calculated as shown
Explanation:
Data:
Let the moisture content be = 0.6
the free moisture content be = 0.08
total moisture of the clay = 0.64
total drying time for the period = 8 hrs
then if the final dry and wet masses are calculated, it follows that
t = (X0+ Xc)/Rc) + (Xc/Rc)* ln (Xc/X)
= 31.3 min.