Question

A site is compacted in the field, and the dry unit weight of the compacted soil (in the field) is determined to be 18 kN/m3. Determine the relative compaction if the maximum dry unit weight was measured to be 17 kN/m3. Express your answer as a percentage (but do not write the percentage sign in the answer box).

Answer 1

Answer:

the relative compaction is 105.88 %

Explanation:

Given;

dry unit weight of field compaction, $W_d_{(field)}$ = 18 kN/m³

maximum dry unit weight measured, $W_d_{(max)}$ = 17 kN/m³

Relative compaction (RC) of the site is given as the ratio of dry unit weight of field compaction and maximum dry unit weight measured

Relative compaction (RC) = dry unit weight of field compaction / maximum dry unit weight measured

$RC = \frac{W_d_{(field)}}{W_d_{(max)}}$

substitute the given values;

$RC = \frac{18}{17} = 1.0588$

RC (%) = 105.88 %

Therefore, the relative compaction is 105.88 %