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vovikov84 [41]
3 years ago
11

A PV battery system has an end-to-end efficiency of 77%. The system is used to run an all-AC load that is run only at night. The

charge controller efficiency is 96% and the inverter efficiency is 85%. How much energy will need to be gathered by the PV array if the load is 120 watts running for 4 hours per night
Engineering
1 answer:
Gre4nikov [31]3 years ago
3 0

Answer:

763.94Wh

Explanation:

If the load is 120 watts running for 4 hours per night, the energy consumed is

120*4 =480 Wh

So, the energy gathered by the PV array is

E=480/(77%*96%*85%)=763.94Wh

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Air modeled as an ideal gas enters a well-insulated diffuser operating at steady state at 270 K with a velocity of 180 m/s and e
ZanzabumX [31]

Answer:

exit temperature 285 K

Explanation:

given data

temperature T1 = 270 K

velocity = 180 m/s

exit velocity =  48.4 m/s

solution

we know here diffuser is insulated so here heat energy is negleted

so we write here energy balance equation that is

0 = m (h1-h2) + m ×  (\frac{v1^2}{2}-\frac{v2^2}{2})   .....................1

so it will be

h1 + \frac{v1^2}{2} = h2 + \frac{v2^2}{2}      .....................2

put here value by using ideal gas table

and here for temperature 270K

h1 = 270.11 kJ/kg

270.11 + \frac{180^2\times \frac{1}{1000}}{2} = h2 + \frac{48.4^2\times \frac{1}{1000}}{2}  

solve it we get

h2 = 285.14 kJ/kg

so by the ideal gas table we get

T2 = 285 K

4 0
3 years ago
A manufacturer makes two types of drinking straws: one with a square cross-sectional shape, and the other type the typical round
Harlamova29_29 [7]

Answer:

\frac{Q_{square}}{Q_{circle}} =  0.785  

Explanation:

given data

types of drinking straws

  1. square cross-sectional shape
  2. round shape

solution

we know that both perimeter of the cross section are equal

so we can say that

perimeter of square  = perimeter of circle  

4 × S = π × D

here S is length and D is diameter

S = \frac{\pi D}{4}        ....................1

and

ratio of  flow rate through the square and circle is here

\frac{Q_{square}}{Q_{circle}} = \frac{AV^2}{AV^2}  

\frac{Q_{square}}{Q_{circle}} = \frac{S^2}{\frac{\pi D^2}{4}}  

\frac{Q_{square}}{Q_{circle}} = \frac{(\frac{\pi D}{4})^2}{\frac{\pi D^2}{4}}  

\frac{Q_{square}}{Q_{circle}} = \frac{\pi }{4}  

\frac{Q_{square}}{Q_{circle}} =  0.785  

4 0
3 years ago
Which step in the engineering design phase is requiring concussion prevention from blows up to 40 mph an example of?
Charra [1.4K]

Answer:

Target your customers

Explanation:

took the test :)

6 0
3 years ago
(a) In a 3-phase, 4-wire system, the currents are in the A, B, and C lines under abnormal conditions of loading were as follows:
Verizon [17]

Answer:

Check the attached image below

Explanation:

Kindly check the attached image below to get the step by step explanation to the question above.

5 0
3 years ago
the AADT for a section of suburban freeway is 150000 veh/day. Assuming this is an urban radial facility, what range of direction
igomit [66]

Answer:

design hour volumes will be 4000 to 6000

Explanation:

given data

AADT  = 150000 veh/day

solution

we get here design hour volumes that is express as

design hour volumes  = AADT × k × D    ..............1

here k is factor and its  range is 8 to 12 % for urban

and D is directional distribution i.e traffic equal divided by the direction

so here design hour volumes will be 4000 to 6000

7 0
3 years ago
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