$(x - 2)^2=49\\ \\ x^2-4x +4 -49=0\\ \\x^2-4x -45 = 0\\ \\\Delta = b^{2}-4ac = (-4)^{2}-4*1* (-45)= 16+180=196 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{4-\sqrt{196}}{2}=\frac{4-14}{2}=\frac{-10}{2}=-5 \\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{4+\sqrt{196}}{2}=\frac{4+14}{2}=\frac{18}{2}=9 \\ \\Answer : \ x=-5 \ or \ x= 9$

8 0

3 years ago

Read 2 more answers

[7m+3n-11-2m]+[n+5-m-3n+8]

labwork [276]

7m-2m+3n-11+n+5-m-3n+8
4m-8+n
answer=4m-8+n

3 0

3 years ago

I need to know the surface area of both 1 and 2 please

sergey [27]

Answer:

1. 142 in.²

2. 190 cm²

Step-by-step explanation:

Both solids are rectangular prisms.

Surface area of a rectangular prism = 2(LW + LH + HW)

1. L = 7 in.

W = 3 in.

H = 5 in.

Plug ok the values into the formula

Surface area = 2(7*3 + 7*5 + 5*3)

= 142 in.²

2. L = 10 cm

W = 3 cm

H = 5 cm

Plug ok the values into the formula

Surface area = 2(10*3 + 10*5 + 5*3)

= 190 cm²

3 0

3 years ago