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Marianna [84]
3 years ago
7

The Polygons below are similar. Find the value of x. A. 4.5 B. 7.5 C. 12 D. 16

Mathematics
1 answer:
koban [17]3 years ago
3 0
I'm pretty sure that it is C. 12 
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Steve's nut world increases the weight of its big almond bag by 3 ounces seven big almond bags now weigh a total of 126 ounces .
Yuliya22 [10]
126/7=18 (so that's 18 ounces per bag) 
now subtract the 3 ounces that were added to each bag:
18-3=15
so the old almond bag weighed 15 ounces 
3 0
3 years ago
Please help a brotha out and i'll give you brainliest
xz_007 [3.2K]

Answer:

First box: 15 * 10^10.

Second box: 300,000,000 meters per second.

Third box: 48 * 10^-13 meters.

Fourth box: 167 * 10^-29 meters.

Step-by-step explanation:

These should be correct! I put them in order from the top empty box to the bottom empty box!!!

Please mark brainliest if correct!!!

3 0
3 years ago
Find a − b when a = −7 and b = 11.
Mariana [72]

Answer:

-18

Explanation:

a - b

a = -7

b = 11

Insert -7 for 'a' and 11 for 'b'

-7 - 11

= -18

3 0
3 years ago
PLEASE HELP ME NOW! THIS IS DUE AND I NEED HELP, please and thank you.
GaryK [48]
Hfdjuggb 77₽+I /2-1₽5
3 0
2 years ago
In the third degree polynomial function f(x) =x^3 + 4x, why are 2i and -2i zeros?
IgorC [24]

Answer:

We just need to evaluate and get f(2i)=0, f(-2i)=0.

Step-by-step explanation:

Since i^2=-1, then i^3=i^2i=-i, and we can apply this when we evaluate f(x) =x^3 + 4x for 2i and -2i.

First we have:

f(2i) =(2i)^3 + 4(2i)=2^3i^3+8i=8(-i)+8i=0

Which shows that 2i is a zero of f(x).

Then we have:

f(-2i) =(-2i)^3 + 4(-2i)=(-2)^3i^3-8i=-8(-i)-8i=8i-8i=0

Which shows that -2i is a zero of f(x).

4 0
3 years ago
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