Answer:
- The function f(x) = 9,000(0.95)^x represents the situation.
- After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
- The range values, in the context of the situation, are limited to whole number
Step-by-step explanation:
The "growth" rate is -5%, so the growth factor, the base in the exponential equation, is 1.00-5% =0.95.
Using x=2, we find the population in 2 years is expected to be about ...
f(2) = 9000·0.95^2 ≈ 8123 . . . . about 8120
Using x=4, we find the population in 4 years is expected to be about ...
f(4) = 9000·0.95^4 ≈ 7331 . . . . about 7330
Since population is whole numbers of bees, the range of the function is limited to whole numbers.
The domain of the function is numbers of years. Years can be divided into fractions as small as you want, so the domain is not limited to whole numbers.
The choices listed above are applicable to the situation described.
Answer:
Step-by-step explanation:
1 ) Y∝ 1 / X
Y = k / X
Y = 9 , X = -5
Putting the values in the relation above
9 = k / - 5
k = -45
Y = - 45 / X
Put Y = - 6
- 6 = - 45 / X
X = - 45 / -6
= 7.5
2 )
Luke and Nora can peel 12 carrots in 5 minutes
in 1 minute Luke and Nora can peel 12 / 5 carrot
in 1 minute Luke alone can peel 12/ 11 carrot .
In 1 minute Nora alone will peel (12 / 5 - 12/ 11 ) carrot
(12 / 5 - 12 / 11 )
= 2.4 - 1.1
= 1.3 carrot
In 1 minute Nora alone will peel 1.3 carrot
1.3 carrot in 1 minute
8 carrot in 8 / 1.3 minute
= 6.15 minutes.
In 1 minute Nora alone will peel 8 carrot in 6.15 minutes working alone.
Answer:
7 is the greatest number of bags Jason can fill.
Step-by-step explanation:
Given: Jason has 14 raspberry scones and 35 blackberry scones.
Now, finding the maximum number of bags Jason can fill with equal number of raspberry scones and blackberry scones.
∴ we will be using Greatest common factor (GCF) for knowing the number of bags.
∴ 
7 is the greatest number of bags that Jason can fill with equal number of raspberry and blackberry scones.
