Question

Simpson drives his car with an average velocity of 48.0 km/h to the east. How long will it take him to drive 144 km on a straight highway? How much time would Simpson save by increasing his average velocity to 56.0 km/h to the east?

Answer 1

Answer:

The time save by Simpson is 25.8 minutes.

Explanation:

Given that,

Velocity of the car, v = 48 km/h

Distance covered by the car, d = 144 km

Let t is the time taken by the car. Speed of an object is given by distance covered per unit time. It is given by :

$v=\dfrac{d}{t}$

$t=\dfrac{d}{v}$

$t=\dfrac{144\ km}{48\ km/h}$

t = 3 hours

If the velocity is increased to 56 km/h to the east. Time taken is given by :

$t'=\dfrac{144\ km}{56\ km/h}$

t' = 2.57 seconds

The time save by Simpson increasing his average velocity is given by :

$\Delta t=t-t'$

$\Delta t=3-2.57$

$\Delta t=0.43\ hours$

or

$\Delta t=25.8\ min$

So, the time save by Simpson is 25.8 minutes. Hence, this is the required solution.