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blsea [12.9K]
4 years ago
8

How is meiosis like binary fission?​

Physics
1 answer:
borishaifa [10]4 years ago
5 0
Miosis is simair to mitosis that create gamtetes and zyotes together
You might be interested in
A famous physics tale is about a rich man who was found dead. He was
anyanavicka [17]
<h2>Answer: C) He could have thrown the bag of money sideways, creating a  horizontal reaction force on himself.</h2>

Explanation:

According to Newton's third law of motion, when two bodies interact between them, appear equal forces and opposite senses in each of them.

To understand it better:

Each time a body or object exerts a force on a second body or object, it (the second body) will exert a force of equal magnitude and direction but in the opposite direction on the first.

So, if the rich man had pushed the bag of money horizontally opposite of where he was, he could have saved himself.

7 0
3 years ago
If you have 30 amps, how much charge moves past a point in the circuit in 120 seconds.
dolphi86 [110]
Q = I t = 30 x 120 = 3600 C
6 0
4 years ago
A sprinter with a mass of 65 kg reaches a speed of 10 m/s during a race. Find the sprinter’s change in linear momentum.
sergiy2304 [10]

Answer:

fuuuuuuuuuuuuuuuck

Explanation:

4 0
3 years ago
A.5 kg model rocket launches with a thrust of 5 n in the upward direction. can it lift off of the ground? (hint: gravity is pull
Sphinxa [80]

Answer:

F = F2 - F1     where F is the net force upwards

F = 5 - (.5 * 9.8) = (5 - 4.9) N = .1 N

Since there is a net force in the upwards direction the rocket should experience an upwards acceleration.

8 0
3 years ago
Three point charges are on the x axis: −1 µC
Nina [5.8K]

Answer:

0.0078 N

Explanation:

The electrostatic force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

The force is attractive if the two  charges have opposite sign, and repulsive if the two charges have same sign.

In this problem, we have:

q_1 = -1 \mu C = -1 \cdot 10^{-6}C located at x_1=-3 m

q_2=+9 \mu C = +9\cdot 10^{-6}C located at x_2=0 m

q_3 = -5 \mu C = -5\cdot 10^{-6} C located at x_3=+3 m

The force between charge 1 and charge 2 is:

F_{12}=k\frac{q_1 q_2}{(x_2-x_1)^2}=(8.99\cdot 10^9)\frac{(1\cdot 10^{-6})(+9\cdot 10^{-6})}{3^2}=0.0090 N

And since the two charges have opposite sign, the force is attractive, so the force on charge 1 is towards the right.

The force between charge 1 and charge 3 is:

F_{13}=k\frac{q_1 q_3}{(x_3-x_1)^2}=(8.99\cdot 10^9)\frac{(1\cdot 10^{-6})(5\cdot 10^{-6})}{6^2}=0.0012 N

And since the two charges have same sign, the force is repulsive, so the force on charge 1 is towards the left.

Therefore, the net  force on charge 1 is:

F=F_{12}-F_{13}=0.0090-0.0012 = 0.0078 N

towards the right.

5 0
3 years ago
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