X is the number of dog
y is the number of cats , y=40
25% of x is 25*x /100=25x/100=x/4
<span>and there are 25% more cats than dogs means y+ x/4=x implies 40=(3/4)x
</span>x=160/3=53
so the number of dogs is 53 and the number of cats is 40
the total number is 53+40=93
Answer:
a=7.85-1/2^b
Step-by-step explanation:
2a=15.7-b Move variable to the right side and change its sign
2a=15.7-b Divide both sides of the equation by 2
a=7.85-1/2^b The final solution for a is
Answer:
30
Step-by-step explanation:
2/9 and 5/6 have a lcm of 30.
4.5/9. It is technically an improper fraction but it still counts.
Make an equation system based on the problem
eg. a is the first number and b is the seond number
An equation for "<span>The sum of two numbers is 53" is
</span>⇒ a + b = 53
An equation for "<span>twice the first number minus three times the second number is 26"
</span>⇒ 2a - 3b = 26
<span>
Solve the equations by elimination and subtitution method
Eliminate a to find the value of b
a + b = 53 (multiplied by 2)
2a - 3b = 26
--------------------------------------
2a + 2b = 106
2a - 3b = 26
------------------- - (substract)
5b = 80
b = 80/5
b = 16
Subtitute the value of b to one of the equations
a + b = 53
a + 16 = 53
a = 53 - 16
a = 37
The numbers are 16 and 37</span>
